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Irina-Kira [14]

3 years ago

7

A car is traveling 71.4 kilometers per hour. What is its speed in miles per minute? One kilometer = 0.62 miles.

1 answer:

Nimfa-mama [501]3 years ago

5 0

$71.4 \times 0.62 = 44.268$

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What are some of the ways that people can Reduce their use of fossil fuels?

alukav5142 [94]

Answer:

By using renewable energy sources.

Explanation:

You need to satisfy a quota of energy for (whatever country you live in). People do this by using the cheapest way of producing the most energy, the most efficient. Sounds great right? Wrong! It stuffs our atmosphere with harmful gasses like carbon dioxide. You can reduce the use of these fossil fuels by using renewable energy sources such as windmills, watermills, and most notable, solar panels!

5 0

3 years ago

Read 2 more answers

Which gas would have the slowest rate of diffusion, assuming that all gases are at the same temperature?

Iteru [2.4K]

Answer: radon (atomic mass 222 amu

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

atomic mass of krypton= 83.8 amu

atomic mass of argon= 39.95 amu

atomic mass of xenon = 131.3 amu

atomic mass of radon= 222 amu

Thus as atomic mass of radon is highest, its rate of diffusion is slowest.

7 0

3 years ago

When 55.0 grams of metal at 75.0°C is added to 100. grams of water at 15.0°C, the temperature of the water rises to 18.7°C. Assu

olga2289 [7]

Answer:

The specific heat of the metal is 0,50 J/gºC

Explanation:

Assume that no heat is lost to the surroundings

(Q = m . C . ΔT)metal + (Q = m . C . ΔT)water = 0

Let's replace our values.

55g . C . (18,7ºC - 75ºC) + 100g . 4,184 J/g·°C . (18,7ºC - 15ºC) = 0

55g . C . -56,3 ºC + 418,4J/·°C . 3,7ºC = 0

-3096,5 gºC . C + 1548,08 J = 0

1548,08 J = 3096,5 gºC . C

1548,08 J / 3096,5 gºC = C = 0,50 J/gºC

8 0

3 years ago

Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu

ad-work [718]

Initial volume of the balloon = $V_{1}$ = 348 mL

Initial temperature of the balloon $T_{1}$ = $25.0^{0}C + 273 = 298 K$

Final volume of the balloon $V_{2}$ = 322 mL

Final temperature of the balloon = $T_{2} = ?$

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

$\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }$

On plugging in the values,

$\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }$

$T_{2} =276 K$

Therefore, the temperature of the freezer is 276 K

5 0

3 years ago

A simple machine produces 25 joules of output work for every 50 joules of input work . What is the efficiency of this machine ?

nataly862011 [7]

2:1, output is half the input

8 0

3 years ago