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hoa [83]
3 years ago
12

Regions in DNA that encodes for

Chemistry
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

A gene is a region of DNA that encodes function. A chromosome consists of a long strand of DNA containing many genes. A human chromosome can have up to 500 million base pairs of DNA with thousands of genes.

Explanation:

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__is when two genetic sequences bind together because of the hydrogen bonds that form between the base pairs ​
Anettt [7]

Answer:

I would say that it is the bond called complementary hydrogen bonds

Explanation:

The nucleotides in a base pair are complementary which means their shape allows them to bond together with hydrogen bonds. The A-T pair forms two hydrogen bonds. The C-G pair forms three. The hydrogen bonding between complementary bases holds the two strands of DNA together.

6 0
4 years ago
Someone help me with this rly quick
Masja [62]

Answer:

10500600m/s

1ds=100m/s

5 0
3 years ago
Substances A and B are combined. When combined, substance A, which is a black solid, sinks to the bottom of substance B which is
Makovka662 [10]

Answer:

c thats just what i do

Explanation:

4 0
3 years ago
Read 2 more answers
Consider reaction AgCIO3(aq)+Mgl2(aq)
mash [69]

Answer:

the product is Mg(Clo3)2 + AgI

6 0
3 years ago
Use the following balanced reaction to solve:
Naily [24]

Answer:  60.7 g of PH_3 will be formed.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given volume}}{\text{Molar volume}}    

\text{Moles of} H_2=\frac{60L}{22.4L}=2.68moles

The balanced chemical reaction is

P_4(s)+6H_2(g)\rightarrow 4PH_3(g)

H_2 is the limiting reagent as it limits the formation of product and P_4 is the excess reagent.

According to stoichiometry :

6 moles of H_2 produce = 4 moles of PH_3

Thus 2.68 moles of H_2 will produce=\frac{4}{6}\times 2.68=1.79moles  of PH_3

Mass of PH_3=moles\times {\text {Molar mass}}=1.79moles\times 33.9g/mol=60.7g

Thus 60.7 g of PH_3 will be formed by reactiong 60 L of hydrogen gas with an excess of P_4

3 0
3 years ago
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