I will give brainliest to best answerFactorise completely (3x^2-5y^2)

1 answer:

6 0

<h2><em>we can write (3x^2-5y^2) as (3x-5y)^2</em></h2><h2><em>( 3 x − 5 y ) 2 as ( 3 x− 5 y ) ( 3 x− 5 y )</em></h2><h2><em>3 x ( 3 x − 5 y ) − 5 y ( 3x −5 y )</em></h2><h2><em>3 x ( 3 x − 5 y ) − 5 y (3 x − 5 y )</em></h2><h2><em>3 x ( 3 x ) + 3 x ( − 5y ) − 5 y ( 3 x ) − 5 y( -5 y )</em></h2><h2><em>9 x 2 − 15 x y − 15y x + 25 y 2 </em></h2><h2><em> Subtract 15 y x from − 15 x y .</em></h2><h2><em>9 x 2 − 30 xy + 25 y 2</em></h2><h2><em> HOPE IT HELPS(◕‿◕✿) </em></h2><h2><em> SMILE!! </em></h2>

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Answer:

The conjecture is that the unit digit of 4^n = 4 when n = odd also 4^n = 6 when n = even

Step-by-step explanation:

$4^1 = 4\\4^2 = 16\\4^3 = 64\\4^4 = 256 \\4^5 = 1024\\4^6 = 4096\\4^7 = 16384\\4^8 = 65536$

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To prove this conjecture

$4^1 = 4\\4^2 = 16$ unit digit = 6

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The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify $[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2$ and to find the value of s in $x^s$ .

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

$=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}$
Comparing with $x^S$
s = -16/3