3 years ago

What degree of rotation about the origin will cause the triangle below to map onto itself?

Mathematics

2 answers:

NARA [144]3 years ago

8 0

Answer:

360

Step-by-step explanation:

AVprozaik [17]3 years ago

4 0

Answer:

=360

explanation:

When you’re talking about rotation you go counterclockwise and each quadrant is another 90 degrees.

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Scorpion4ik [409]

Answer:

-25,-1.3, -0.45, 7.3, I-50I

Step-by-step explanation:

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3 years ago

The value of y varies directly with x, and y<br> Find y when x = 2.4.<br> 7.2 when x = 1.6.

Nady [450]

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2 years ago

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Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN.

shtirl [24]

Given that <span>point L is between M and N on MN. Then
MN = ML + LN
31 = h - 15 + 2h - 8 = 3h - 23
3h = 31 + 23 = 54
h = 54/3 = 18

Therefore, LN = 2(18) - 8 = 36 - 8 = 28.
</span>

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3 years ago

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Aleksandr-060686 [28]

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7 0

2 years ago

The intensity of a light source at a distance is directly proportional to the strength of the source and inversely proportional

jolli1 [7]

Answer:

x= $\frac{16}{\sqrt[3]{2}+1 }$

Step-by-step explanation:

Q= illumination

I = intensity

Q= I/d^2

Q_total = $\frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}$

= $\frac{I}{x^2}+\frac{2I}{(16-x)^2}$

now Q' = 0

⇒I ${-\frac{2}{x^3}}+\frac{4}{(16-x)^3}$

x= $\frac{16}{\sqrt[3]{2}+1 }$

[/tex] $\frac{1}{x^3} = \frac{2}{(16-x)^3}$

x= $\frac{16}{\sqrt[3]{2}+1 }$

is the required point

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2 years ago