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3 years ago

Which expression is equivalent to (4x^5+11)^2 ?

Mathematics

2 answers:

ale4655 [162]3 years ago

7 0

The correct answer is c

Amiraneli [1.4K]3 years ago

7 0

Answer: Option C is correct that is $16x^{10} +121+88x^5$

Explanation:

we have been given with the expression

$(4x^5+11)^2$

we will use the formula of

$(a+b)^2=a^2+b^2+2ab$

Here a is equal to $4x^5$

And b is equal to 11 substituting the values of a,b in the formula we will get

$(4x^5+11)^2=(4x^5)^2+11^2+2(4x^5)(11)\\\\=16x^{10} +121+88x^5$

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Answer:

B) 5, 20, 80, 320

Step-by-step explanation:

Complete question

Given the recursive formula shown, what are the first 4 terms of the sequence?

f(1) = 5 if n=1

f(n) = 4f(n-1) if n> 1

A) 5. 25, 100, 400

B) 5, 20, 80, 320

C) 5, 25, 125, 625

D) 5. 14, 60, 236

Get f(2)

f(2) = 4f(2-1)

f(2) = 4f(1)

f(2) = 4(5)

f(2) = 20

Get f(3)

f(3) = 4f(3-1)

f(3) = 4f(2)

f(3) = 4(20)

f(3) = 80

Get f(4)

f(4) = 4f(4-1)

f(4) = 4f(3)

f(4) = 4(80)

f(4) = 320

Hence the first 4 terms of the sequence are 5, 20, 80 and 320

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Bingel [31]

Answer:

Step-by-step explanation:

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Answer:

<u> </u><u>-1 </u>

Step-by-step explanation:

Given that:

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