Answer: It is 1 int count = 0;
2 for (int i = n; i >= 0; i /= 2)
3 count += i;
4 for (int j = 0; j < n; j++)
5 count +=j;
6 return count;
SO it is j(0-(-n)
Explanation: Im dum
Answer:
4 and 50
Explanation:
To answer the question above, we are to first of all consider the size of union will be the max size of datatype in union data. I.E.
sizeof(int *) is 4 bytes
so, sizeof(U) = sizeof(temp) is 4
and we saved 50 in temp.i1. so, 50 we can access 50 from temp.i2 as well
so, output is 4 and 50
It's called an <span>RSS (Really Simple Syndication).
</span>A Web service that aggregates selected information from various Web resources, including newsgroups, blogs, forums, and other news and information services and delivers it to a user ' s desktop in a convenient, easy-to-use format.
Answer:
if (arr[i] > max) -> max3 = max2, max2 = max , max = arr[i]. else if (arr[i] > max2) -> max3 = max2, max2 = arr[i]. else if (arr[i] > max3) -> max3 = arr[i]. At the end of the loop, we will print all three values.
Answer:
3. WiFi Protected Access 2
Explanation:
Given that Wi-Fi Protected Access 2 often referred to as WAP 2 is a form of computer security or privacy measure to ensure that Wireless networks are furnished with powerful security of data network access control.
Hence, when a user employed or utilize WPA2. It gives such a user a high degree of maximum certainty of controlling the users that can have access to his wireless network.
Hence, in this case, what is put in place to stop such activity is Wi-Fi Protected Access 2
