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lara [203]
3 years ago
12

Please help me with this please

Mathematics
2 answers:
ololo11 [35]3 years ago
8 0

always remember

\sqrt[i]{ {a}^{b} }  =  {a}^{ \frac{b}{i} }

except in cases that <i> is even & b is less than zero, or A will have a negative power.

here you have:

{x}^{ \frac{1}{3} +  \frac{5}{2}  + 1 } \div  {x}^{ \frac{1}{2} }

and a simple job:

\frac{1}{3}  +  \frac{5}{2}  + 1 -  \frac{1}{2 }  =  \frac{1}{3 }  +  \frac{4}{2}  + 1 = 3  +  \frac{1}{3}

finally answer is:

{x}^{ \frac{10}{3} }  =  {x}^{3}   \sqrt[3]{x}

Andrew [12]3 years ago
5 0

Answer:

answer iy in the picture...

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Answer:

<u>The correct answer is D.  x + 5≤ - 4</u>

Step-by-step explanation:

Let's review which inequality has - 12 in its solution set, this way:

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D. x + 5 less-than-or-equal-to negative 4

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see explanation

Step-by-step explanation:

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Step-by-step explanation:

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