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joja [24]
3 years ago
13

#12. How is the answer 48? How do I get it?

Mathematics
2 answers:
aliina [53]3 years ago
6 0

Alright, so we've established that the true answer is 48, but we need to understand how to get that.

We know the equation is (t/4) - 3 = 9

First, we need to add 3 to both sides. You should come up with: t/4 = 12

Now, when you have a fraction like that, you need to multiply by the denominator on both sides, no matter what the numerator may be. Therefore:

t/4 (4) = 12(4)

t = 48

<em>As another example</em> to enhance your understanding, let's use (x/5) - 6 = 10.

You'd begin by adding 6 to each side: (x/5) = 16.

Then, multiply by 5 (the denominator) on both sides.

x = 80.

VashaNatasha [74]3 years ago
3 0
You do 9+3 which equals 12 then you multiply that by 4
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2 years ago
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Phoenix [80]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Factor x^3 -7x^2 -5x+35 by grouping. what is the resulting expression
Anni [7]

Answer:

(x-7) (x^2-5)

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x^3 -7x^2 -5x+35

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8 0
3 years ago
A carpenter is assigned the job of expanding a rectangular deck where the width is one-fourth the length. The length of the deck
leva [86]
Let the width be W, then the length is 4W (since the width is 1/4 the length)

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so the area of the new deck is :

(4W+6)(W+2)= 4W^{2}+8W+6W+12= 4W^{2}+14W+12

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Answer: width: 4, length: 16
3 0
3 years ago
How do i prove 2sec^2x-2sec^2xsin^2-sin^2x-cos^2x=1
kramer
2\sec^2x-2\sec^2x\sin^2x-\sin^2x-\cos^2x=2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)

Since \sin^2x+\cos^2x=1, you have

2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)=2\sec^2x\cos^2x-1

and since \sec x=\dfrac1{\cos x}, you end up with 2-1=1.
6 0
3 years ago
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