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Anastaziya [24]
3 years ago
6

For each expression listed, is it a difference of squares? Explain yes or no and why or why not. Explain in enough detail so the

re is no doubt that it is or isn't a difference of squares. 1. y5 − 25 2. 9m2n2 − 121 3. p18 − q10 4. 16r2 − 27
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0
<h2>Explanation:</h2><h2></h2>

If we can write a polynomial in the form a^2-b^2, then we can factor it as:

a^2-b^2=(a-b)(a+b)

In this problem, we have the following expressions:

1. \ y^5 - 25 \\ \\  2. \ 9m^2n^2-121  \\ \\ 3. p^{18} - q^{10} \\ \\ 4. 16r^2 - 27

  • For 1 and 4 we can't write this in the form a^2-b^2 so this is not a difference of squares.

  • For 2:

9m^2n^2-121 =3^2m^2n^2-11^2 \\ \\ =(3mn)^2-11^2 =(3mn-11)(3mn+11)

So we could write 2 as a difference of squares.

  • For 3:

p^{18} - q^{10}=(p^9)^2-(q^5)^2=(p^9-q^5)(p^9+q^5) \\ \\ \\ Remember: \ (a^m)^n=a^{mn}

So we could write 2 as a difference of squares.

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3 years ago
7) -6x + 6y=6<br> -6x + 3y=-12
Gre4nikov [31]

Answer:

(5,6)

Step-by-step explanation:

-6x+6y=6

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Multiply the first equation by -1

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Add this to the second equation

6x-6y=-6

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---------------------

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Divide each side by -3

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Now we need to find x

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3 0
3 years ago
If A is a square matrix of order 2, then det(-3A) is *
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Answer:

c. 9 det A

Step-by-step explanation:

Given the following data;

Since A is a square matrix of order 2, we know that n = 2

K = 3

For any scalar k;

∣kA∣ = k^{n} ∣A∣

<em>Substituting into the equation;</em>

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Simplifying, we have;

∣-3A∣ = 9∣A∣

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<em>Therefore, det (-3A) = 9 detA</em>

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