Answer:
m = 28
Step-by-step explanation:
The two triangles are similar, therefore we can make proportions
36/24 = 42/m
m = 42(24)/36 = 28
Answer:
(e) the mean number of siblings for a large number of students has a distribution that is close to Normal.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
By the Central Limit Theorem
The sampling distributions with a large number of students(at least 30) will be approximately normal, so the correct answer is given by option e.
Answer:
net income is $48452.81
Step-by-step explanation:
Sales =$147500
subtract operating expenses
-$75500 =$72000
subtract non- operating costs
depreciation -$10200 =$61800
-interest expense payable (16500*7,23%)$1196.25=63603.75
from profit before tax deduct income taxes =63603.75*25%=15150.9375
Net Income is therefore $63603.75-$15150.9375 = $48452.81
I believe it’s the last one.
(a)
Q1, the first quartile, 25th percentile, is greater than or equal to 1/4 of the points. It's in the first bar so we can estimate Q1=5. In reality the bar includes values from 0 to 9 or 10 (not clear which) and has around 37% of the points so we might estimate Q1 a bit higher as it's 2/3 of the points, say Q1=7.
The median is bigger than half the points. First bar is 37%, next is 22%, so its about halfway in the second bar, median=15
Third bar is 11%, so 70% so far. Four bar is 5%, so we're at the right end of the fourth bar for Q3, the third quartile, 75th percentile, say Q3=40
b
When the data is heavily skewed left like it is here, the median tends to be lower than the mean. The 5% of the data from 80 to 120 averages around 100 so adds 5 to the mean, and 8% of the data from the 60 to 80 adds another 5.6, 15% of the data from 40 to 60 adds about 7.5, plus the rest, so the mean is gonna be way bigger than the median of around 15.