Answer:
Keep temperature constant and increase the pressure of the reaction. The rate of reaction increases.
Explanation:
First of all, the question is asking us to design an experiment to investigate the effect of pressure on the rate of reaction hence the pressure can not be held constant since it is the variable under investigation. This eliminates the first option.
Secondly, increasing the pressure of the reaction means that particles of the gas collide more frequently leading to a greater number of effective collisions and a consequent increase in the rate of reaction according to the collision theory.
Hence the answer above.
Answer:
Explanation:
You can calculate the entropy change of a reaction by using the standard molar entropies of reactants and products.
The formula is
The equation for the reaction is
C₂H₄(g) + 3O₂(g) ⟶ 2CO₂(g) + 2H₂O(ℓ)
ΔS°/J·K⁻¹mol⁻¹ 219.5 205.0 213.6 69.9
Answer:
8.36 x 10 to the 24 power molecules of water in a cup of water
Explanation:
Answer:
The answer is 0.844/10 minutes
Explanation:
You have an enzyme that catalizes a reaction which gives a product that can be quantified by an absorbance measurement. The more reaction time, the more product quantity and higher absorbance.
The rate of the reaction is the change in products quantity per time unit. As you are using the absorbance as a measure of the product quantity, you can calculate the rate as the change in absorbance (ΔA) per time (in minutes) as follows:
rate= ΔA/time
rate= (final absorbance - initial absorbance) /minutes
rate= (0.444-0.022)/5 min
rate= 0.422/5 min
In 10 minutes will be :
rate= 0.844/10 min
Commonly, a rate is the relation between two quantities measured in different units. For example, the speed of a car is the change in meters (traveled distance) per time (m/s or km/h). For an enzyme, is the same (quantity of product/time).
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