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adoni [48]
3 years ago
9

The Transition Elements can be divided into two types. List each type.

Chemistry
1 answer:
jenyasd209 [6]3 years ago
7 0
Main group elements
transition metals
lanthanides
actindes.
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The type of compound that is most likely to contain a covalent bond is ________.
max2010maxim [7]
The type of substance that is most likely to contain a covalent bond is ONE THAT IS COMPOSED OF ONLY NON METALS.
Covalent bond is a type of chemical bond in which electron pairs are shared among the participating elements in order to achieve the octet form. Covalent bond is usually found among non metals.
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3 years ago
Did diagram shows embryo development of four different animals. How is this evidence used to suggest that life changes over time
wel
It suggests that life changes over time by showing different animals at different stages in their life, also giving more than one example on how they can change during early development and throughout their lives
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3 years ago
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How can cool red giant be more luminous than a warmer main sequence star?
ruslelena [56]

Answer: C

Explanation:

5 0
3 years ago
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PLEASE HELP
Olenka [21]
There is no reaction because of the common ion effect(which in this case is K)if there were a reaction the products would be the same as the reactants so no reaction happens
5 0
3 years ago
Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at
kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}

Squaring both sides, we get

(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}

Solve for <em>M</em>₂:

M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}

M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}

= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}

7 0
3 years ago
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