E and Dis determine the H
212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.
Answer:
Option A.
Explanation:
Similar to Avagadro's law, there is another law termed as dilution law. As the product of volume and normality of the reactant is equal to the product of volume and normality of the product from the Avagadro's law. In dilution law, it will be as product of volume and concentration of the solute of the reactant is equal to the product of volume and concentration of solution.

So, as per the given question C1 = 5.45 M of lead nitrate and V1 has to be found. While C2 is 1.41 M of lead nitrate and V2 is 820.7 ml.
Then, 

So nearly 212 ml of lead nitrate is required to prepare a dilute solution of 820.7 ml of lead nitrate.
You would have to evaporate the water to get just the sugar
The correct option is A. Rutherford model of the atom consider an atom to be made up of a central nucleus with electrons orbiting around it. The nucleus is considered to be tiny, heavy and its positively charged while the electrons are negatively charged. The shortcoming of this model is that it was not able to explain how the positive nucleus was not able to attract the negative electrons and pull them inside the nucleus.
Most of the NADH that delivers electrons to the electron transport chain comes from the citric acid cycle and or the kreb's cycle.