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Crazy boy [7]
2 years ago
13

Measures of central angles and measures of inscribed angles

Mathematics
1 answer:
N76 [4]2 years ago
6 0

Answer:

could you give details

Step-by-step explanation:

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Is the number there three? if you answer to me i will give you twenty Points.
juin [17]

Answer:

2

Step-by-step explanation:

3 x 2 = 6

1 x 2 = 2

hope it helps

sorry if I'm wrong

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1 year ago
Please help ASAP!!<br><br><br> Will Mark Brainiest
mr Goodwill [35]
I am pretty sure its JT
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tigry1 [53]

Answer:

70/100

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Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Segments DF, DH, and GF are tangent to the circle. Andrew was asked to find DF. Explain andrew's error.
ANEK [815]

Answer:

DF = 14

Step-by-step explanation:

Andrew was wrong in the assumption that DE = EF

Segments of tangents to a circle from the same external point are congruent

That is

EF = FG = 8

Then

DF = DE + EF = 6 + 8 = 14

5 0
2 years ago
skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.
Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T        O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T       B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = \left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]

= a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] +b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] +c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]

therefore Basis of W is

={ {\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right] ,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]}

8 0
3 years ago
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