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Dafna1 [17]
3 years ago
11

Can someone help me understand this? Because I really don’t understand this at all

Mathematics
1 answer:
Otrada [13]3 years ago
7 0

Answer: I believe it is A OR B

Step-by-step explanation: BECAUSE IF A⇒B AND B⇒C

THEN  ¬A⇒C  I THINK ITS A THO

OR ¬A⇒¬C

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According to the National Vital Statistics, full-term babies' birth weights are Normally distributed with a mean of 7.5 pounds a
Sav [38]

Answer:

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 7.5, \sigma = 1.1

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So

X = 8.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.6 - 7.5}{1.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 6.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.4 - 7.5}{1.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

6 0
3 years ago
How do I begin this equation
alex41 [277]
Trigonometry:
We know that   csc x = 1 / sin x    and π = 180°;
sin 5π/ 6 = sin 150° = 1/2
csc 2π / 3 = 1 / sin 120° = 1 / √3/2 = 2 / √3
Finally:
4 · 1/2 + 7 · ( 2 / √3 )² = 2 + 7 · 4/3 = 
= 2 + 28/3 = 2 + 9 1/3 =  11  1/3
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Alinewithaslopeof7passesthroughthepoint
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Y=7x+3 because slope intercept form is y=mx+b where x is the slope and b is the y intercept so when you plug in the slope of 7 and the y intercept of 3 you get the equation y=7x+3.
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We only consider the portion of the graph from x=0 on, since negative time is illogical.  Tracing the graph we get the intersection point.

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