Answer:
equation;

Center (-4,2)
Radius is

Step-by-step explanation:
Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

Where (h,k) is center
r is the radius
So first we group like Terms together

Add 7 to both sides


Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

and

so we have



To find our center, h is -4 and k is 2
so the center is (-4,2)
The radius is

So the radius is 3 times sqr root of 3.
Answer:
false
Step-by-step explanation:
A linear equation has x to the first power
or of the form x plus a constant
This has x to the fifth power so it is not linear
Answer:
90 and 10
Step-by-step explanation:
The third one would be the correct answer. I separately multiplied each number in the first section by each number in the second section. For instance, 0 x 2 is 0, 4 x 5 is 20, 5 x 3 is 15, and 2 x 0 is 0. All of these numbers are in the third answer.
Answer:
(-3,5)
Step-by-step explanation:
In reflections the x axis is the opposite only