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Luden [163]
3 years ago
12

Write a short paragraph to answer the following question.

Mathematics
1 answer:
Harrizon [31]3 years ago
8 0
The four transformations:
Translation, Rotation, Reflection, and Scaling

Each of these transformations change how or where the shape is. Each of these transformations change the shape or shapes in different ways. Dilations change the size and sometimes even the shape of the shape; translation, rotation, and reflection just move the shape around they don't change the size or shape of it.

Is that what you are looking for? Let me know if there anything more...
You might be interested in
Consider the first four terms of the sequence below.
Lelu [443]

Answer:

a₈ = -  1 / 128

Step-by-step explanation:

Given:

First four terms of the sequence

a₁= 1, a₂= - 1/2, a₃= 1/4 and a₄= -1/8

First we recognize that this is a geometric series (sequence) and we must calculate quotient q.

q = a₂/a₁ = a₃/a₂ = (-1/2)/1 = (1/4)/(-1/2) = - 1/2

q = - 1/2

Formula for calculating n-th term is:

aₙ = a₁ · qⁿ⁻¹

According to this:

a₈ = 1  (-1/2)⁷ = - 1/ 128

God with you!!!

8 0
3 years ago
A. 2 cm<br>B. 2√2 cm<br>C. 4 cm<br>D. 4√2 cm​
algol [13]

Answer:

.D. 4√2 cm

Step-by-step explanation:

With reference angle 45°

base (b) = 4 cm

hypotenuse (h) = AC

Now

Cos 45° = b /h

1/√2 = 4 / AC

AC = 4√2 cm

3 0
3 years ago
Which of the following variables is Nominal? Select one: a. Age (in years) b. Age (grouped as: less than 18, 18-29, 30-59, 60 an
Arada [10]

Answer:

c. Car color (e.g. red, blue, grey)

Step-by-step explanation:

There are four level of measurements: Ordinal, Nominal, Interval and Ratio.

  1. Ordinal variables are categorical variables and have a ordered categories. For example,the health of patients: Excellent, Good, Average and Poor.
  2. Nominal variables are also categorical variables but they do not have a ordered category or any numerical value. For example, Gender: Male or Female, or Occupation:, Accountant, Clerk, Manager.
  3. Interval variable are variables that take numerical values. These variables are ordered and  the difference between two values is meaningful. For example, temperature in degrees F.
  4. Ratio variable are type of interval variables but they do not have a variables with a 0 measurement. For example, height, age, money.

Considering all the option:

(a) Age (in years) is an interval variable.

(b) Age grouped as < 18, 18 - 29, 30-59, 60 > are basically ordered categorical variables. Thus, they are ordinal variables.

(c) Car Color (red, blue, grey) are nominal variable because they are not ordered and cannot be measured.

(d) Letter grade in a course (A+, A, A-, B+, B) are also ordinal variables because they are ordered and represent the performance quality of the student.

Thus, the correct answer is (c).

4 0
3 years ago
Two consecutive integers have a sum of 153. find the integers.
Natasha2012 [34]
X = first integer
x + 1 = second consecutive integer

x + (x + 1) = 153..combine like terms
2x + 1 = 153
2x = 153 - 1
2x = 152
x = 152/2
x = 76

x + 1 = 76 + 1 = 77

so ur numbers are : 76 and 77...and u will find that when added equal 153.
6 0
3 years ago
The average maximum monthly temperature in Campinas, Brazil is 29.9 degrees Celsius. The standard deviation in maximum monthly t
kvv77 [185]

Answer:

P(X>32)=P(\frac{X-\mu}{\sigma}>\frac{32-\mu}{\sigma})=P(Z>\frac{32-29.9}{2.31})=P(z>0.909)

And we can find this probability with the complement rule and using the normal standard distributon table or excel we got:

P(z>0.909)=1-P(z

And if we convert this to a % we got 18.2 % of maximum temperatures higher or equal than 32 C

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the maximum monthly temperature of a population, and for this case we know the distribution for X is given by:

X \sim N(29.9,2.31)  

Where \mu=29.9 and \sigma=2.31

We are interested on this probability

P(X>32)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>32)=P(\frac{X-\mu}{\sigma}>\frac{32-\mu}{\sigma})=P(Z>\frac{32-29.9}{2.31})=P(z>0.909)

And we can find this probability with the complement rule and using the normal standard distributon table or excel we got:

P(z>0.909)=1-P(z

And if we convert this to a % we got 18.2 % of maximum temperatures higher or equal than 32 C

8 0
3 years ago
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