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GalinKa [24]
3 years ago
14

The age of a boy is twice that of his sister. five years ago the boy was 3 times the age of his sister. How old is the boy

Mathematics
1 answer:
joja [24]3 years ago
7 0

<em>Answer</em><em>:</em>

<h2><em>2</em><em>0</em><em> </em><em>years</em><em> </em><em>old</em><em>.</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>Let</em><em> </em><em>the</em><em> </em><em>age</em><em> </em><em>of</em><em> </em><em>sister</em><em> </em><em>be</em><em> </em><em>X</em>

<em>Let</em><em> </em><em>the</em><em> </em><em>age</em><em> </em><em>of</em><em> </em><em>boy</em><em> </em><em>be </em><em>2</em><em>x</em>

<em>Now</em><em>,</em>

<em>Five</em><em> </em><em>years</em><em> </em><em>ago</em><em>,</em>

<em>3(x - 5) = 2x - 5 \\ or \: 3x - 15 = 2x - 5 \\ or \: 3x - 2x =  - 5 + 15 \\ x = 10</em>

<em>Again</em><em>,</em>

<em>Repla</em><em>cing</em><em> </em><em>value</em><em>,</em>

<em>age \: of \: boy = 2x \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 2 \times 10 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 20</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

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A given population proportion is .25. What is the probability of getting each of the following sample proportions
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This question is incomplete, the complete question is;

A given population proportion is .25. What is the probability of getting each of the following sample proportions

a) n = 110 and = p^ ≤ 0.21, prob = ?

b) n = 33 and p^ > 0.24, prob = ?

Round all z values to 2 decimal places. Round all intermediate calculation and answers to 4 decimal places.)

Answer:

a) the probability of getting the sample proportion is 0.1660

b) the probability of getting the sample proportion is 0.5517

Step-by-step explanation:

Given the data in the questions

a)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 110

mean = μ = 0.25

S.D = √( p( 1 - p) / n ) = √(0.25( 1 - 0.25) / 110 ) √( 0.1875 / 110 ) = 0.0413

Now, P( p^ ≤ 0.21 )

= P[ (( p^ - μ ) /S.D) < (( 0.21 - μ ) / S.D)

= P[ Z < ( 0.21 - 0.25 ) / 0.0413)

= P[ Z < -0.04 / 0.0413]

= P[ Z < -0.97 ]

from z-score table

P( X ≤ 0.21 ) = 0.1660

Therefore, the probability of getting the sample proportion is 0.1660

b)

population proportion = 0.25

q = 1 - p = 1 - 0.25 = 0.75

sample size n = 33

mean = μ = 0.25

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= P[ Z > ( 0.24 - 0.25 ) / 0.0754 )

= P[ Z > -0.01 / 0.0754  ]

= P[ Z > -0.13 ]

= 1 - P[ Z < -0.13 ]

from z-score table

{P[ Z < -0.13 ] = 0.4483}

1 - 0.4483

P( p^ > 0.24 )  = 0.5517

Therefore, the probability of getting the sample proportion is 0.5517

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