An urn contains n red balls and m blue balls. They are withdrawn one at a time until a total of r, r ≤ n, red balls have been wi
thdrawn. Find the probability that a total of k balls are withdrawn. Hint: A total of k balls will be withdrawn if there are r − 1 red balls in the first k − 1 withdrawals and the kth withdrawal is a red ball.
1 answer:
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If a marble is randomly selected from the box, then the probability
that it is small or green is 0.7297
Step-by-step explanation:
A box contains 19 large marbles and 18 small marbles
Each marble is either green or white
9 of the large marbles are green, and 8 of the small marbles are white
If a marble is randomly selected from the box, we need to find the
probability that it is small or green
1. Find P(small) ⇒ P(s)
2.Find P(green) ⇒ P(g)
3. Find P(small and green) ⇒ P(s and g)
4. Use the rule P(small or green) = P(s) + P(g) - P(s and g)
∵ The box contains 19 large marbles and 18 small marbles
∴ The total number of marbles = 19 + 18 = 37
∴ P(s) =
∵ There are 8 small white marbles
∵ There are 18 small marbles
∴ The number of small green marbles = 18 - 8 = 10
∴ P(s and g) =
∵ There are 9 large green marbles
∵ There are 10 small green marbles
∴ The number of green marbles = 9 + 10 = 19
∴ P(g) =
∵ P(small or green) = P(s) + P(g) - P(s and g)
∴ P(small or green) =
∴ P(small or green) = = 0.7297
If a marble is randomly selected from the box, then the probability
that it is small or green is 0.7297
Learn more:
you can learn more about probability in brainly.com/question/13053309
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