You roll a fair 6-sided die.<br> What is P(roll less than 4)?

Kaylis [27]

Here’s everything you might need to know! hope this helps!!

Square root of 586 definition
The square root of 586 in mathematical form is written with the radical sign like this √586. We call this the square root of 586 in radical form. The square root of 586 is a quantity (q) that when multiplied by itself will equal 586.

√586 = q × q = q2

Is 586 a perfect square?
586 is a perfect square if the square root of 586 equals a whole number. As we have calculated further down on this page, the square root of 586 is not a whole number.

586 is not a perfect square.
Is the square root of 586 rational or irrational?
The square root of 586 is a rational number if 586 is a perfect square. It is an irrational number if it is not a perfect square. Since 586 is not a perfect square, it is an irrational number. This means that the answer to "the square root of 586?" will have an infinite number of decimals. The decimals will not terminate and you cannot make it into an exact fraction.

√586 is an irrational number

Can the square root of 586 be simplified?
You can simplify 586 if you can make 586 inside the radical smaller. We call this process "to simplify a surd". The square root of 586 cannot be simplified.

√586 is already in its simplest radical form.

How to calculate the square root of 586 with a calculator
The easiest and most boring way to calculate the square root of 586 is to use your calculator! Simply type in 586 followed by √x to get the answer. We did that with our calculator and got the following answer with 9 decimal numbers:

√586 ≈ 24.207436874

6 0

3 years ago

PLEASE Help this is due today

andrey2020 [161]

B. 3
—-
11 775 x b- 6

Yuh!!

7 0

3 years ago

Read 2 more answers

Identify the domain of the function shown in the graph.

Leno4ka [110]

Domain is set of all x-values. You are supposed to focus on the x-axis instead.

From the graph, the point starts from x = -5 and ends on x = 5. That means no values would exist after x = 5 or before x = -5.

Hence, the domain starts from -5 to 5.

Answer

-5≤x≤5

4 0

3 years ago

HELP ME PLEASE I DONT UNDERSTAND!!!!!

rewona [7]

Answer: 5 pounds

Step-by-step explanation: 90 - 47.65 ÷ 8.47 = 5

8 0

3 years ago

Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa

xxMikexx [17]

Answer:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins. Yes No Total

Small 32 18 50

Medium 68 7 75

Large 89 11 100

_____________________________________

Total 189 36 225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1: NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{50*189}{225}=42$

$E_{2} =\frac{50*36}{225}=8$

$E_{3} =\frac{75*189}{225}=63$

$E_{4} =\frac{75*36}{225}=12$

$E_{5} =\frac{100*189}{225}=84$

$E_{6} =\frac{100*36}{225}=16$

And the expected values are given by:

Size Company/ Heal. Ins. Yes No Total

Small 42 8 50

Medium 63 12 75

Large 84 16 100

_____________________________________

Total 189 36 225

And now we can calculate the statistic:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

3 0

3 years ago

You roll a fair 6-sided die. What is P(roll less than 4)?