I need to know what 803 divided by 8 is

1 answer:

5 0

$\underline{100.375}\\803:8\\\underline{8}\\.0\\\underline{.0}\\.\ 3\\\underline{.\ 0}\\.\ 30\\\underline{.\ 24}\\.\ \ 60\\\underline{.\ \ 56}\\.\ \ \ 40\\\underline{.\ \ \ 40}\\.\ \ R=0\\------------\\\boxed{803:8=100.375}$

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The rule for the number of fish in a home aquarium is 1 gallon of water for each inch of fish length. Marta's aquarium holds 33

tigry1 [53]

<h3>Answer:</h3>

A: 7 inches
B: 6 inches

<h3>Step-by-step explanation:</h3>

We can let the variables A and B stand for the length in inches of fish A and fish B, respectively.

If we assume each person bought fish having a total length of 1 inch per gallon of aquarium, then we can write equations ...

... 3A +2B = 33 . . . . . total length of Marta's fish

... 3A +4B = 45 . . . . . total length of Hank's fish

Subtracting the first equation from the second, we get ...

... 2B = 12

... B = 6 . . . . . divide by 2

Using this value in the first equation, we have ...

... 3A + 2·6 = 33

... 3A = 21 . . . . . . . . subtract 12

... A = 7 . . . . . . . . . . divide by 3

Fish A is 7 inches long; fish B is 6 inches long.

6 0

3 years ago

a conference will take place in a large hotel meeting room. The organizers of the conference have created a drawing to determine

Bogdan [553]

Answer:

313 ft

Step-by-step explanation:

If 12in = 12 ft

313in = x

= 313 ft

4 0

3 years ago

The average number of newspapers for sale in an airport stand is 15. SD is 6. The average age of the pilots is 36 and SD is 4. W

balu736 [363]

Answer:

The average age of pilots has a lower coefficient of variation, so it is the most consistent data set.

Step-by-step explanation:

The coefficient of variation is used to measure consistency of a data set. It is the standard deviation divided by the mean. The higher the coefficient of variation, the more variable, that is, the least consistent the data set is.

The average number of newspapers for sale in an airport stand is 15. SD is 6.

The consistency is:

$C = \frac{6}{15} = 0.4$