Go step by step to reduce the radical.
1 answer:
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<h2>Answer: Lines b & c are parallel.⇄</h2>
Step-by-step explanation:
- When lines are perpendicular, the product of their slope is -1 (the slopes are negative reciprocal).
- When lines are parallel, they have the same slope.
Slope = ( y₂ - y₁) / (x₂ - x₁)
Slope of Line b = ( 6 - 1 ) ÷ ( 1 - 9 )
= 5 ÷ (- 8)
= - ⁵/₈
Slope of Line c = ( 12 - 7 ) ÷ ( 2 - 10 )
= - ⁵/₈
⇒ Line b ║ Line c
Answer:
We draw line AB which is perpendicular to the 14 cm side
Since Angle C is 60 degrees that makes angle CAB = 30 degrees
Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm
Line BD equals 9 cm
Line AB^2 = 10^2 - 5^2 = 75
Line AD^2 = AB^2 + BD^2
Line AD^2 = 75 + 81
Line AD^2 = 156
Line AD = 12.4899959968
Line AB = Sqr root (75) = 8.6602540378
Angle D = arc sine (8.6602540378 / 12.4899959968)
Angle D = 43.898 degrees
Angle A = 180 - 60 - 43.898 = 76.102 degrees
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Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.
Step-by-step explanation:
