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lawyer [7]
3 years ago
14

Fine the distance d(A,B)between Points A and B. A(4,-4);B(4,4)

Mathematics
2 answers:
Mariulka [41]3 years ago
7 0

Answer:

Distance: 8

Step-by-step explanation:

d = sqrt [(x-x)^2 + (y-y)^2]

d = sqrt [(4-4)^2 + (-4-4)^2]

d = sqrt(0) + (-8)^2

d = sqrt 64 = 8

hjlf3 years ago
3 0

Answer:

d=8

Step-by-step explanation:

u should use this formula to find the distance'd'.

d=

\sqrt{(x2 - x1) power2 + (y2 - y1)power2

I hope it will help u.

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Which expression is even for all integers a and b?
Irina18 [472]
Do u have a problem that went with this?

3 0
3 years ago
Read 2 more answers
Find the function r that satisfies the given condition. r'(t) = (e^t, sin t, sec^2 t): r(0) = (2, 2, 2) r(t) = ()
lesantik [10]

Answer:

r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2)

Step-by-step explanation:

A primitive of e^t is e^t+c, since r(0) has 2 in its first cooridnate, then

e^0+c = 2

1+c = 2

c = 1

Thus, the first coordinate of r(t) is e^t + 1.

A primitive of sin(t) is -cos(t) + c (remember that the derivate of cos(t) is -sin(t)). SInce r(0) in its second coordinate is 2, then

-cos(0)+c = 2

-1+c = 2

c = 3

Therefore, in the second coordinate r(t) is equal to -cos(t)+3.

Now, lets see the last coordinate.

A primitive of sec²(t) is tan(t)+c (you can check this by derivating tan(t) = sin(t)/cos(t) using the divition rule and the property that cos²(t)+sin²(t) = 1 for all t). Since in its third coordinate r(0) is also 2, then we have that

2 = tan(0)+c = sin(0)/cos(0) + c = 0/1 + c = 0

Thus, c = 2

As a consecuence, the third coordinate of r(t) is tan(t) + 2.

As a result, r(t) = (e^t +1, -cos(t) + 3, tan(t) + 2).

6 0
3 years ago
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Minchanka [31]

Answer:

J (6,2) K (2,2)

Step-by-step explanation:

Now distance of AB = [(y2-y1)^2 + (x2-x1)^2]^(1/2)

                                = 8 units

CB =  [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 6 units by using same formula

Now AB/CB must equal to GH/HJ as rectangles are similar

GH =  [(y2-y1)^2 + (x2-x1)^2]^(1/2)

= 4 units

so

8/6 = 4/HJ

So,

HJ = 3 units

Now if we see the coordinates given carefully, it is obvious that two perpendicular lines lie perfectly parallel to x and y coordinates in rectangle ABCD.  A is (-7,-2) and B is (1,-2) which means distance along y-axis doesn't change. Similarly for C (1,-8) and D (-7,-8), one can see that distance between y-axis doesn't change. So lines AB and CD of rectangle are parallel with x and AD and BC are parallel with y-axis.

In rectangle GHJK one can see that in given coordinates, G(2,5) and H(6,5), y coordinate is same so it is parallel to x axis. Now, HJ is perpendicular to GH so it must be parallel to y axis. It means if we know the lengths of sides we can easily determine unknown coordinates by simple addition and subtraction.

So,  we know HJ = 3 units

J is (6,2) since HJ is parallel to y axis so distance on x axis will remain unchanged and length of line HJ will effect distance of y axis.

Similarly K is (2,2) for the same reason.

6 0
3 years ago
Can someone help and tell me how you got the answer
neonofarm [45]

Answer:

x = 15

Step-by-step explanation:

x/3 + 10 =15

Subtract 10 from each side

x/3+10-10 =15-10

x/3 = 5

Multiply each side by 3

x/3*3 = 5*3

x=15

8 0
3 years ago
3, 12, 48, 192, 768, . . . This sequence has a?
nydimaria [60]

Answer:

common ratio is 4

Step-by-step explanation:

3, 12, 48, 192, 768, . . .

LEts find the common difference

12-3= 9

48-12= 36

There is no common difference

LEts find out common ratio by dividing the second term by first term

\frac{12}{3} =4

\frac{48}{12} =4

\frac{192}{48} =4

So common ratio is 4

8 0
3 years ago
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