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3 years ago

12

adam used the three fraction s to make a circle graph and colored each a different color. what fraction of the graph is not colo

red?

2 answers:

DochEvi [55]3 years ago

8 0

If there were no division of circle before, the answer is 0

Luba_88 [7]3 years ago

4 0

1/3 is your answer......

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Solve 2a−5≤13.<br><br> help please

rosijanka [135]

Answer:

a≤9

Step-by-step explanation:

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The polynomial factor to X^3 + 2x^2-3x

dangina [55]

Answer:

$x(x-1)(x+3)$

Step-by-step explanation:

Factor out the common terms, and get: $x(x^2+2x-3)$

Factor $(x^2+2x-3)$ , and get: $(x-1)(x+3)$

<em>Hope this helps!!</em>

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3 years ago

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Answer:

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Step-by-step explanation:

1. A horizontal number line is shown with labels at negative 50, 0, and 35. A red arrow (labeled withdrew 50 dollars) begins at 0 and ends at negative 50. A blue arrow (labeled deposited 35 dollars) begins at 0 and ends at 35.

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2 years ago

Mr Smith had 4 daughters each daughter had a brother.. How children does Mr Smith have?

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3 years ago

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A research engineer for a tire manufacturer is investigating tire life for a new rubber compound. She has built 10 tires and tes

n200080 [17]

Answer:

The standard deviation of tire life does exceed 3000 km

Step-by-step explanation:

This is a Chi-Square Hypothesis Test for the Standard Deviation, here we have

$\bf H_0: \sigma = 3000$

$\bf H_a: \sigma > 3000$

so, this is an upper one-tailed test.

The <em>test statistic</em> is

$\bf T=\frac{(n-1)s^2}{\sigma^2}$

where

<em>n = 10 is the sample size</em>

<em>s = sample standard deviation</em>

$\bf \sigma$ = population standard deviation

we would reject the null hypothesis if

$\bf T>\chi^2_{(\alpha,n-1)}$

where

$\bf \chi^2_{(\alpha,n-1)}$

is the critical value corresponding to the level of significance $\bf \alpha$ with n-1 degrees of freedom.

we can use either a table or a spreadsheet to compute this value.

In Excel use

CHISQ.INV(0.05,9)

In OpenOffice Calc use

CHISQINV(0.05;9)

and we get this value equals 3.3251

Working out our T statistic

$\bf T=\frac{(n-1)s^2}{\sigma^2}=\frac{9*(2990)^2}{(3000)^2}=8.9401$

Since T > 3.3251 we reject the null and conclude that the standard deviation of tire life exceeds 3000 km.

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