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marishachu [46]

3 years ago

10

10 POINTS!!! FULL ANSWER IN STEP BY STEP FORMAT!!

1 answer:

Lilit [14]3 years ago

4 0

After a little manipulation, the given diff'l equation will look like this:

e^y * dy = (2x + 1) * dx.
x^2
Integrating both sides, we get e^y = 2------- + x + c, or e^y = x^2 + x + c
2

Now let x=0 and y = 1, o find c:

e^1 = 0^2 + 0 + c. So, c = e, and the solution is e^y = x^2 + x + e.

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HELP QUICK PLSSS !!

9966 [12]

Answer:

$\frac{n+8}{3}$

Step-by-step explanation:

6 0

3 years ago

Find the value of x in here

True [87]

Answer:

x=30

Step-by-step explanation:

(3x-10)+(2x-20)=180// 5x-30=180//5x=150//x=30

4 0

3 years ago

Which of the following is true regarding the solution to the logarithmic equation below? log Subscript 2 Baseline (x + 11) = 4.

meriva

Answer:

Option C.

Step-by-step explanation:

The given logarithmic equation is

$\log_2(x+11)=4$

It can be written as

$(x+11)=2^4$ $[\because log_ax=y\Leftrightarrow x=a^y]$

$x+11=16$

$x=5$

Now, to check whether $x=5$ is a true solution or not. Substitute $x=5$ in the LHS of given equation.

$LHS=\log_2(5+11)$

$LHS=\log_2(16)$

$LHS=\log_22^4$

$LHS=4$ $[\because log_aa^x=x]$

$LHS=RHS$

Hence, $x=5$ is a true solution because $\log_2(16)=4$ .

Therefore, the correct option is C.

5 0

2 years ago

Jill, an employee at Old Navy, budgets 18 of her yearly salary for clothing. Jill's total clothing bill for the year is $8,180.

Triss [41]

Answer: $ 45,444.44

Step-by-step explanation:

Given: Jill budgets 18% of her yearly salary for clothing.

His total clothing bill for the year is $8,180.

Let x= her yearly salary

Then according to the question , we have

18% of x = 8180

Convert 18% into decimal by dividing it by 100 , we get

0.18 x= 8180

Multiply both sides by 100

⇒ 18x = 818000

Divide both sides by 18 , we get

x= 45444.44

Hence, her yearly salary = $ 45,444.44

8 0

3 years ago

The graph of the function f(x) = (x − 3)(x + 1) is shown.

Travka [436]

Answer:

Real values of x where x < -1

Step-by-step explanation:

Above the x-axis, the function is positive.

The function is decreasing when the gradient is negative.

The function has a positive

${x}^{2}$

coefficient, therefore the vertex is a local minimum;

This means the gradients are negative before the vertex and positive after it;

To meet the conditions therefore, the function must be before the vertex and above the x-axis;

This will be anywhere before the x-intercept at x = -1;

Hence it is when x < -1.

8 0

3 years ago

Read 2 more answers