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yaroslaw [1]
3 years ago
8

Help your girl out! :) be kind pls

Mathematics
2 answers:
lukranit [14]3 years ago
5 0

Answer: Bottom Right, the figure must have right angles.

The rest all make sense, inculding the bottom right answer, but it said "must have right angles."

nadezda [96]3 years ago
3 0

Answer:

Step-by-step explanation:

.

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A line m is perpendicular to an angle bisector of ∠A. The sides of ∠A intersect this line m at points M and N. Prove that △AMN i
Ray Of Light [21]

Answer:


Step-by-step explanation:

<em><u>Given</u></em><u>:</u>       A line m is perpendicular to the angle bisector of ∠A. We call this  

                 intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.

                 AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.

<u><em>To Prove</em></u>:   <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>

<em>                    </em><em><u>equal. </u></em>

<em><u>Solution</u></em>:  Now, In ΔADM and ΔADN

                 ∠MAD=∠NAD     ...(1) (∵Given)

                  AD=AD                ...(2) (∵common side)

                  ∠ADM=∠ADN     ...(3) (∵Given)

                  <u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>

                                                         ( ∵ ASA  congruence rule)

                  ⇒<u><em> AM=AN</em></u>

                  Now, In Δ AMN

                 AM=AN (∵ Proved)

                  Hence, ΔAMN is an isosceles  triangle.


7 0
3 years ago
Mary can travel 174 miles in 3 hours.at this rate how far can she travel in 7 hours
Aneli [31]
174/3=58 miles in one hour 7*58=406 miles
or you and do 7/3*174=406
8 0
3 years ago
a plane flying with the wind travels 630 mi in 1.5hrs. Flying against the wind , the plane travels 1120 mi in 4hrs. Find the rat
Flauer [41]
\bf \begin{cases}&#10;r=\textit{rate of the plane}\\&#10;w=\textit{rate of the wind}\\&#10;\end{cases}&#10;\\\\&#10;&#10;\begin{array}{ccccllll}&#10;&distance&rate&time(hrs)\\&#10;&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\&#10;\textit{with wind}&630&r+w&1\frac{1}{2}\\&#10;\textit{against wind}&1120&r-w&4&#10;\end{array}&#10;

\bf thus  \begin{cases}&#10;630=(r+w)1\frac{1}{2}\to 630=(r+w)\frac{3}{2}&#10;\\\\&#10;1120=(r-w)4\\&#10;--------------\\&#10;630=(r+w)\frac{3}{2}\implies 630\cdot \frac{2}{3}=r+w\\&#10;420=r+w\implies \boxed{420-w}=r\\&#10;--------------\\&#10;thus\\&#10;--------------\\&#10;1120=(r-w)4\implies 1120=4r-4w&#10;\\\\&#10;1120=4(\boxed{420-w})-4w&#10;\end{cases}&#10;

solve for "w", to find the wind's speed rate,

so hmmm what's the plane's rate?  well 420 - w = r  :)
5 0
2 years ago
Evaluate (2.4x10^4) (4.5x10^3)
goldfiish [28.3K]

Answer:

108000000x^2

Step-by-step explanation:

6 0
2 years ago
What is the greatest to least from this equation 5.132 5.123 5.312 5.231<br>​
kondor19780726 [428]

Answer:

5.312 (Greatest)

5.231

5.132

5.123 (Least)

Hope this helps!! <3

7 0
3 years ago
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