Given:
Composite figure.
The figure splitted into two shapes.
One is vertical cuboid and other is horizontal cuboid
To find:
Total surface area of the figure
Solution:
<u>Vertical cuboid:</u>
Length = 14 inches
Width = 12 inches
Height = 24 inches
Surface area = 2(lw + wh + lh)
= 2(14 × 12 + 12 × 24 + 14 × 24)
= 2(168 + 288 + 336)
Surface area = 1584 square inches
<u>Horizontal cuboid:</u>
Length = 14 inches
Width = 10 inches
Height = 30 - 12 = 18 inches
Surface area = 2(lw + wh + lh)
= 2(14 × 10 + 10 × 18 + 14 × 18)
= 2(140 + 180 + 252)
Surface area = 1144 square inches
Total surface area = 1584 + 1144
= 2728 square inches
The total surface area of the figure is 2728 square inches.
Answer:
if 9 ants=3.51inches
25 ants =x
therefore by cross multiplication
x= 25*3.51 /9 =9.8 inches
answer:B
Hi!
Two negatives make a positive, so this can be rewritten as
-7+2.5
The answer is D. -7+2.5
Hope this helps! :)
-Peredhel
Answer
Find out the how many pounds of metal are in 1,950 lb of ore .
To proof
let us assume that the pounds of metal are in 1,950 lb of ore be x .
As given
In an ore, 9.8% of its total weight is metal.
ore weight = 1,950 lb
9.8% is written in the decimal form
![= \frac{9.8}{100}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B9.8%7D%7B100%7D)
= 0.098
Than the equation becomes
x = 0.098 × 1950
x = 191.1 pounds
Therefore the 191.1 pounds of metal are in 1,950 lb of ore .
Hence proved
Answer:
Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.
Now, we have numbers lying between the square of n and (n + 1) is 2n
⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112
Hence, 112 numbers lies between the square of the given numbers.