Answer:
There is an 88% probability that a course has a final exam or a research paper.
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
E is the probability that a course has final exam.
P is the probability that a course requires research paper.
We have that:

In which e is the probability that a course has final exam but does not require research paper and
is the probability that a course has both of these things.
By the same logic, we have that:

(a) Find the probability that a course has a final exam or a research paper.
This is

Suppose that 26% of courses have a research paper and a final exam.
This means that

43% of courses require research papers.
So 



71% of courses have final exams
So 



The probability is

There is an 88% probability that a course has a final exam or a research paper.