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erma4kov [3.2K]
3 years ago
12

At a college, 71% of courses have final exams and 43% of courses require research papers. Suppose that 26% of courses have a res

earch paper and a final exam. Part (a) Find the probability that a course has a final exam or a research paper.
Mathematics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

There is an 88% probability that a course has a final exam or a research paper.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

E is the probability that a course has final exam.

P is the probability that a course requires research paper.

We have that:

E = e + (E \cap P)

In which e is the probability that a course has final exam but does not require research paper and E \cap P is the probability that a course has both of these things.

By the same logic, we have that:

P = p + (E \cap P)

(a) Find the probability that a course has a final exam or a research paper.

This is

Pr = e + p + (E \cap P)

Suppose that 26% of courses have a research paper and a final exam.

This means that

E \cap P = 0.26

43% of courses require research papers.

So P = 0.43

P = p + (E \cap P)

0.43 = p + 0.26

p = 0.17

71% of courses have final exams

So E = 0.71

E = e + (E \cap P)

0.71 = e + 0.26

e = 0.45

The probability is

Pr = e + p + (E \cap P) = 0.45 + 0.17 + 0.26 = 0.88

There is an 88% probability that a course has a final exam or a research paper.

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Step-by-step explanation:

When we select r things from n things in a order , we use permutations.

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Then, the number of possible orders are = ^9P_3=\dfrac{9!}{(9-3)!}

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A. Only Graph A is a function.
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What is the missing step in solving the inequality 5 – 8x < 2x + 3? Add 2x to both sides of the inequality. Subtract 8x from
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Answer:

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Step-by-step explanation:

First, you subtract by 5 from both sides of equation.

5-8x-5<2x+3-5

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Then subtract by 2x from both sides of equation.

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