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2 years ago

How do u write an equation in standard form containing the points (0,2) and (-4,1)

Mathematics

1 answer:

-Dominant- [34]2 years ago

8 0

Answer:

y=1/4+2

Step-by-step explanation:

If we're using y=mx+b, then m is the slope and b is the y intercept. The slope of the two points provided, is 1/4. The y intercept, is two.

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Brady had a balance of $23 before a $25 fee was charged to his account. what is his new balance?

sdas [7]

Answer:

$48

Step-by-step explanation:

23+25=48

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2 years ago

Solve for x to the nearest tenth.

bogdanovich [222]

Answer: the answer to your question is 8.0

Step-by-step explanation:

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Multiply each side by 10

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2 years ago

how much would $600 invested at 8% interest compound continuously be worth after 3 years? round to the nearest cent a(t)=p.ert

Aleksandr-060686 [28]

Given:
$600 principal
8% rate = 8/100 = 0.08
3 years time

Solving for A:
A = P⋅e^rt
where:
A is the amount
P is the principal
e is the mathematical constant
r is the rate of interest
t is the time in years

A = P⋅e^rt
= 600⋅e^(0.08⋅3)
= 600(2.718281828459045)^(0.24)
A = $762.70

$600 compounded continuously at a rate of 8% for 3 years will yield a final amount of $762.70

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3 years ago

Which of the following is the graph of y=5?

AysviL [449]

I can't see the rest of the graphs.

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3 years ago

Read 2 more answers

Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

2 years ago