Ask question

Ask question

All categories

3 years ago

6

The length of a rectangle is 3.5 inches more tan its width. The perimeter of the rectangle is 31 inches. Find the length and the

width of the rectangle. Explain

1 answer:

leonid [27]3 years ago

8 0

Length (L): w + 3.5

width (w): w

Perimeter (P) = 2L + 2w

31 = 2(w + 3.5) + 2(w)

31 = 2w + 7 + 2w

31 = 4w + 7

24 = 4w

6 = w

Length (L): w + 3.5 = (6) + 3.5 = 9.5

Answer: width = 6 inches, length = 9.5 inches

You might be interested in

andriy [413]

It's -18.

-1/6b=3

Multiply the reciprocal of -1/6 to both sides, this will get x by itself

(-6/1)*-1/6b=3*(-6/1)

b= -18/1
b= -18

3 0

3 years ago

Read 2 more answers

The cheerleading team lines up down the football field to rally the spectators. If there are 12 cheerleaders, which

Elan Coil [88]

Answer:

So they can line up every single 10 yards because there are 120 yards on a football field

Step-by-step explanation:

12 cheerleaders gives you 1 every 10 yards

hope i helped

8 0

3 years ago

PLEASE HELP!!! I AM DESPERATE BECAUSE MY CLASS IS IN A FEW MINUTES. Solve using statement reason.

svlad2 [7]

Answer:

Statement 1. P

Reason 1. Theorem: The measure of an external angle of a triangle is equal to the sum of the measures of the remote interior angles.

Statement 2. 132 = 3x + 54

Statement 3. x = 26

6 0

3 years ago

PLEASE HELP. it is in the attachment

juin [17]

Answer:

<JKL=123

Step-by-step explanation:

57+57=114

360-114=246

246/2=123

<JKL=123

3 0

3 years ago

Read 2 more answers

An isosceles trapezoid ABCD with height 2 units has all its vertices on the parabola y=a(x+1)(x−5). What is the value of a, if p

horrorfan [7]

Answer:

a = -0.3575

Step-by-step explanation:

The points A and D lie on the x-axis, this means that they are the x-intercepts of the parabola, and therefore we can find their location.

The points A and B are located where

$y=a(x+1)(x-5)=0$

This gives

$x=-1$

$y=5$

Now given the coordinates of A, we are in position to find the coordinates of the point B. Point B must have y coordinate of y=2 (because the base of the trapezoid is at y=0), and the x coordinate of B, looking at the figure, must be x coordinate of A plus horizontal distance between A and B, i.e

$B_x=A_x+\frac{2}{tan(60)} =-1+\frac{2\sqrt{3} }{3}$

Thus the coordinates of B are:

$B=(-1+\frac{2\sqrt{3} }{3},2)$

Now this point B lies on the parabola, and therefore it must satisfy the equation $y=a(x+1)(x-5).$

Thus

$2=a((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)$

Therefore

$a=\frac{2}{((-1+\frac{2\sqrt{3} }{3})+1)((-1+\frac{2\sqrt{3} }{3})-5)}$

$\boxed{a=-0.3575}$

8 0

3 years ago