Answer:
The probability that all are male of choosing '3' students
P(E) = 0.067 = 6.71%
Step-by-step explanation:
Let 'M' be the event of selecting males n(M) = 12
Number of ways of choosing 3 students From all males and females

Number of ways of choosing 3 students From all males

The probability that all are male of choosing '3' students


P(E) = 0.067 = 6.71%
<u><em>Final answer</em></u>:-
The probability that all are male of choosing '3' students
P(E) = 0.067 = 6.71%
Hello,
Please, see the attached files.
Thanks.
3+2=5
5x=100%
x=20 (divide)
20*3=60
60% are boys, 40% are girls
Answer:
Draw a line AB
Take a point C on AB
Fix the tip of compass at C and with a fix radius, cut AB on both sides of C
Mark those points D and E
Fix the tip of compass on D, and with the same radius, draw an arc above C
Do the same with E
Those two arcs will intersect at a point, mark the point F
Make a line passing through both C and F
Line CF is perpendicular to AB
You didn't describe the line. / / / / If the equation of the line is [ y = m x + b ] then [ y=(any number) x+b] has the same y-intercept, and [y=mx+any number] is parallel to it.