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egoroff_w [7]
3 years ago
6

PLEASE HELP ill give you 45 points and mark brainliest if it’s correct

Mathematics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

The answers are below,...

Step-by-step explanation:

1. LN = 37

2. NM = 23

3. x = 4

4. EF = 58 / x = 16

5.

6.

7.

8.

Moreover explanation:

Okay so with 5-8 I was unable to figure out the answer,... I guess I shouldn't be answering your questions if I have to figure them out as well. lol,... I did however try (I've been working on just 5-6 for the last hour or so) so I guess brownie points for me for that,... so sorry I couldn't help completely though,... I asked my older brother how to solve them and he is going to get back to me on them (he also has a schedule to keep) I'll hopefully get back to you soon so stay tuned (or not cause hopefully someone else has already answered them) again, so sorry. and the best of luck to you! later!

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Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they
Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276

Number of ways of choosing 3 students From all males

n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220

The probability that all are male of choosing '3' students

P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }

P(E) =  \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0
3 years ago
I have a few questions:
inn [45]
Hello,
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3 0
2 years ago
The Ratio of boys to girls in Martin Middle school is 3/2. what is the percent of the entire school is boys?
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3+2=5

5x=100%

x=20 (divide)

20*3=60

60% are boys, 40% are girls

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3 years ago
Use rulers and compasses to draw a line which is perpendicular to line AB at point C
netineya [11]

Answer:

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Take a point C on AB

Fix the tip of compass at C and with a fix radius, cut AB on both sides of C

Mark those points D and E

Fix the tip of compass on D, and with the same radius, draw an arc above C

Do the same with E

Those two arcs will intersect at a point, mark the point F

Make a line passing through both C and F

Line CF is perpendicular to AB

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You didn't describe the line. / / / / If the equation of the line is [ y = m x + b ] then [ y=(any number) x+b] has the same y-intercept, and [y=mx+any number] is parallel to it.
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