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3 years ago

Is x=-2 a solution of the equation 1-6x=7?

Mathematics

2 answers:

lukranit [14]3 years ago

7 0

No because if you multiply a positive times a negative you will just get a negative and 7 isn't an negative so no.

ivolga24 [154]3 years ago

5 0

In order to figure this out, you must solve the equation.

1-6x=7 (given)

-6x=6 (subtract 1 from both sides)

X=-1 (divide both sides by -6)

The answer is no.

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Simplify the expression:<br> 8d+9c+1x3=b

VMariaS [17]

Answer:

b=8d+9c+3

Step-by-step explanation:

Multiply:

1x3=3

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b=8d+9c+3

Hence, the correct answer is b=8d+9c+3

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2 years ago

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antiseptic1488 [7]

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3 years ago

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Gina wants to take dance classes. She compares two dance studios to determine which has the best deal for her. Dance World charg

fomenos

Answer:

10 classes

Step-by-step explanation:

Given equations in the question

Dance World: y = 15x

Toe Tappers: y = 25 + 12.5x

Where,

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4 0

3 years ago

Simplify 4√16 + 8√16

Mumz [18]

$4\sqrt{16} + 8\sqrt{16}$ :

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$7\sqrt{4} *3\sqrt{8}$

We have $\sqrt{4}=2$

simplify $\sqrt{8} = \sqrt{2^3} = \sqrt{2^2*2}$

then the radical rule is used: $\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}$

⇒ $\sqrt{2^2*2} = \sqrt{2^2} \sqrt{2}= \sqrt{4}\sqrt{2} =2\sqrt{2}$

Now we have $\sqrt{4}=2$ and $\sqrt{8}=2 \sqrt{2}$

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$2\sqrt{4} =2*2= 4$ and $5\sqrt{9} =5*3= 15$

$2\sqrt{4}+5 \sqrt{9} = 4+15 = 19$

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$4\sqrt{5} -2\sqrt{5} = 2\sqrt{5}$

since $2\sqrt{5}$ is the half of $4\sqrt{5}$

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