2x^2 + x + 3=0 has only complex roots.
The determinant is 1-4*2*3 = -23
-23 (or any determinant) is the part under the square root sign, If that determinant is negative, knowing you cannot take the square root of a negative number, we know the answers must be complex.
I think the awkward science is quite amusing to me
We can use the points (2, -2) and (4, -1) to solve.
Slope formula: y2-y1/x2-x1
= -1-2/4-(-2)
= -3/6
= -1/2
Point slope form: y - y1 = m(x - x1)
y - 2 = -1/2(x + 2)
Solve for y-intercept.
-2 = -1/2(2) + b
-2 = -1 + b
-2 + 1 = -1 + 1 + b
-1 = b
Slope Intercept Form: y = mx + b
y = -1/2x - 1
______
Best Regards,
Wolfyy :)
