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2 years ago

12

A number with a negative exponent can always be written using positive exponents in fraction form. the numerator will always be

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please finish the sentence

1 answer:

Elena-2011 [213]2 years ago

8 0

Answer:

1

Step-by-step explanation:

i did this in 8th grade so last year. trust me

can i get brainlest

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Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m

Dovator [93]

Option a: $\frac{m^{5} }{162n}$ is the equivalent expression.

Explanation:

The expression is $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ where $m\neq 0, n\neq 0$

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

$\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }$

Cancelling the like terms, we have,

$\frac{3^{-3}m^{5} n^{-1}}{6 }$

This equation can also be written as,

$\frac{m^{5}}{3^{3}6 n^{1} }$

Multiplying the terms in denominator, we have,

$\frac{m^{5} }{162n}$

Thus, the expression which is equivalent to $\frac{(3m^{-2} n)^{-3}}{6mn^{-2} }$ is $\frac{m^{5} }{162n}$

Hence, Option a is the correct answer.

8 0

3 years ago

Read 2 more answers

Help im in k12 9th grade

dem82 [27]

When factoring find 2 numbers that when added together equal the middle value and when multiplied equal the last value.

min this problem the middle value is 7 and the last value is 10

5 + 2 = 7 and 5 x 2 = 10

The answer is: (x+2)(x+5)

4 0

2 years ago

Read 2 more answers

Twice the sum of Paloma's age and 15 is 106. How old is Paloma?

fredd [130]

Answer: 121

Step-by-step explanation:

4 0

2 years ago

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Solve for x and y <br> 8x-2y=24

TiliK225 [7]

Answer: For y it's y=4x−12 and for x it's x=12+y/4

Step-by-step explanation:

SOLVING FOR X

8x-2y=24

2(4x−y)=24

4x−y=24/2

4x−y=12

4x=12+y

x=12+y/4

SOLVING FOR Y

8x-2y=24

2(4x−y)=24

4x−y=24/2

4x−y=12

−y=12−4x

y=−12+4x

y=4x−12

Hope this helps, have a BLESSED AND WONDERFUL DAY! As well as a great Black History Month and Valentine's day! :-)

- Cutiepatutie ☺❀❤

8 0

2 years ago

G 3.6 Dice rolls. If you roll a pair of fair dice, what is the probability of (a) getting a sum of 1

Paladinen [302]

Answer:

0

Step-by-step explanation:

In the roll of a pair of fair dice, The sample space is as follows:

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

If x,y represent the possible outcome of rolling the two die

Then the total number of possibilities for the sample space = (x,y)

= (6 × 6) = 36

Now, the probability of getting a sum of 1 does not exist in the roll of a pair of fair dice.

Therefore, Probability(1) = 0

8 0

3 years ago