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zzz [600]
3 years ago
9

What's the answer to this? And how do u do it

Mathematics
1 answer:
andrew-mc [135]3 years ago
3 0
-5n - 3 - 3 > 19
-5n - 6 > 19
+ 6 +6
-5n > 25
divide by -5 on each side
change signs since dividing by negative

N< -5

For graphing on the line, you will create an OPEN circle on -5 and sketch it to the left.
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Determine whether the following sampling is dependent or independent. Indicate whether the response variable is qualitative or q
Margarita [4]

Answer:1. Dependent

2.Qualitative Variable

Step-by-step explanation:

Step 1--- Dependent

Reason-- The researcher considers a couple as a whole and The sampling is dependent because a spouce selected for one sample dictates or determines which individual to be in the second sample.

Step 2----Qualitative variable

Reason--- it classifies the individual spouce mental health based on mental health inventory of the couple

Because Qualitative variables are variables which can be placed according to characteristic or attribute, here the characteristics is mental health.

7 0
3 years ago
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Solve the inequality.<br> -5-3x 2(10+2x) + 3<br> The solution is
Alekssandra [29.7K]

Answer:

x<=-4

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3 years ago
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In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir
Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}= p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0204^{2}).

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.96

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0306^{2}).

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.31

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

6 0
3 years ago
Please help meh ill mark braniliest!!​
Crazy boy [7]

Answer:

its -15 !!! its easy!!!!

3 0
3 years ago
You sell T- shirts for a fundraiser. It cost $112 to have the T- shirts made. You make $98 in sales. What is your profit
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You make -$14, or you lose $1
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