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2 years ago

Find m These questions getting hard

Mathematics

1 answer:

pickupchik [31]2 years ago

3 0

Answer:

the

Step-by-step explanation:

it's fairly easy actually. You just have to use sin

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×=3y,×-3y=0 substitution step by step please

krek1111 [17]

Answer:

Step-by-step explanation:

x = 3y.......(1)

x - 3y = 0 ....(2)

Substituting x in (1) into (2)

3y - 3y = 0

No solutions

6 0

3 years ago

Find the general indefinite integral. (use c for the constant of integration. )

Vlada [557]

The indefinite integral will be $\int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)$

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:

$\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C$

Integration Property [Multiplied Constant]:

$\int cf(x)dx=c\int f(x)dx$

Integration Property [Addition/Subtraction]:

$\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx$

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

$\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx -\int 2dx$

[Integrals] Rewrite [Integration Property - Multiplied Constant]:

$\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx -2\int dx$

[Integrals] Reverse Power Rule:

$\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C$

Simplify:

$\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

So the indefinite integral will be $\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C$

To know more about indefinite integral follow

brainly.com/question/27419605

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7 0

2 years ago

Will I ever get an answer?

JulsSmile [24]

(5/8) / (3/8) =
5/8 * 8/3 =
5/3 =
1 2/3....a = 1, b = 2, c = 3

5 0

2 years ago

Help me with number 1 please

viva [34]

17 25 and 1/2 34. 42 and 1/2

3 0

2 years ago

Write an expression that has four terms. Your expression should have three different variables and a constant

raketka [301]

4m+5a+x-6 this is just one example you could switch it around it even use different numbers but that expression does have 4 terms, three different variables, and one constant, hope this helps:)

8 0

2 years ago