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frez [133]
3 years ago
5

Solve 2x^2 – 8x = –7

Mathematics
2 answers:
Goshia [24]3 years ago
6 0
Making one side of the equation zero, the equation becomes,
                                  2x² - 8x + 7 = 0
The value of x may be calculated through the quadratic formula.
                                  x = (-b +/- sqrt(b² - 4ac)) / 2a
where a, b, and c are 2, -8, and 7, respectively. The values are,
                  x = (8 + sqrt (8² - (4)(2)(7))) / 2x2 = -1.29
                 <span> x = (8 - sqrt (8² - (4)(2)(7))) / 2x2 = -2.71</span>
svetoff [14.1K]3 years ago
3 0
\displaystyle 2x^2 - 8x = - 7 \\ \\ 2x^2-8x+7=0 \\ \\  \Delta=b^2-4ac \\ \\ \Delta=(-8)^2-4\cdot2\cdot7 \\ \\  \Delta = 8 \\ \\ X_{1,2}= \frac{-b\pm \sqrt{\Delta} }{2a}  =  \frac{8 \pm 2 \sqrt{2}  }{4} =  \frac{\not2(4\pm \sqrt{2}) }{\not4} = \frac{4\pm \sqrt{2} }{2}
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(50 POINTS)!
Yuliya22 [10]

Answer:

The answer to your question is below

Step-by-step explanation:

When a denominator has a positive exponent we change it into an expression with a negative exponent and vice-versa, when a numerator has a positive exponent, we change it into a denominator with a negative exponent.

a)   \frac{1}{p^{4}} = p⁻⁴

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3 years ago
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Akimi4 [234]
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3 years ago
Help geometry what I m jlf <br> Picture provided
Zolol [24]

Answer:

\angle\,JLF = 114^o  which agrees with option"B" of the possible answers listed

Step-by-step explanation:

Notice that in order to solve this problem  (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from 180^o, since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as 90^o and 138^o. (see attached image)

We put our efforts into solving the right angle triangle denoted with green borders.

Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : 360^o-90^o-138^o=132^o

Therefore, the two equal acute angles in the triangle JOH should add to:

180^o-132^o=48^o resulting then in each small acute angle of measure 24^o.

Now referring to the green sided right angle triangle we can find find angle JLG, using: 180^o-24^o-90^o=66^o

Finally, the requested measure of angle JLF is obtained via: 180^o-66^o=114^o

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