Answer:
K= 44.018%; S= 19.957%; O= 36.025%
Explanation:
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Complex a: <span>tetrachlorocuprate(i)
In present complex chlorine is negatively charged ligand (-1) and oxidation state of copper is +1. Therefore, total charge on complex = 4(-1) + 1 = -3
Complex b: </span><span>pentaamminechlorocobalt(iii)
In present complex, ammine is a neutral ligand (charge = 0), chlorine is negatively charged ligand (charge = -1) and oxidation state of Co is +3. Therefore, total charge on complex is 5(0) + (-1) + (+3) = +2
</span><span>Complex c: diaquadichloroethylenediaminecobalt(iii)
</span>In present complex, aqua is a neutral ligand (charge = 0), chlorine is a negatively charged ligand (charge = -1), ethylenediamine is a neutral ligand (charge = 0) and oxidation state of cobalt is +3. Therefore, total charge on complex is 2(0) + 2(-1) + 2(0) + 3 = +1.
One decimal place.
The reading in graduated cylinder is marked after every 1 mL and that of pipette at every 0.1 mL. If same amount of water is taken from both the containers. The sum of volume of water will take the minimum decimal places. Precise value of volume is calculated using pipette as it has markup after every 0.1 mL, the lowest decimal place will be 1 decimal place (0.1).
Well, when 1-propanol is heated in the presence of an acid produces Cyclopropane and water. one example of this is when we heat propanol (CH3CH2CH2OH) with an acid like HCl. if we do the balancing like this: CH3CH2CH2OH + HCl -> CH3CH2CH2Cl + H2O we obtain the Cyclopropane and water.