All categories

3 years ago

What are 3 pros and cons of nuclear transmutation?

2 answers:

7 0

Pros
It doesn't cost much
Power stations are ver compact
Transportation of the material is easy

Cons
It isn't safe
Nuclear waste take 200 years to degrade
Greater risk of explosion.

alexgriva [62]3 years ago

4 0

Explanation:

When one element or isotope is converted into another chemical element then this process is known as nuclear transmutation.

In nuclear transmutation, there occurs a change in nucleus or core of the atom undergoing the reaction.

Nuclear transmutation is a nuclear reaction and during this reaction there is release of some energy.

Three pros of nuclear transmutation are as follows.

Produced energy can be utilized for any other reaction or work.
It releases green house gases and helps to decrease the effect of global warming.
Emit less amount of carbon dioxide.

Three cons of nuclear transmutation are as follows.

Since nuclear transmutation is a nuclear reaction so there will be production of some radioactive waste which can cause damage or harm to the environment.
Elements used in nuclear transmutation are non-renewable.
The waste produced can not be disposed off easily as the cost to manage nuclear waste is very high.

You might be interested in

BNCT relies on the initial targeting of tumor cells by an appropriate chemical compound tagged with 10 5B, which preferentially

zimovet [89]

Answer:

$^{10}B + ^{1}n_{th} \rightarrow ^{4}He + ^{7}Li + 2.79MeV$

Explanation:

BNCT therapy consists in the irradiation of the atoms of ¹⁰B that are contained in the tissue that has the tumor cells, with thermal neutrons to produce alpha particles and ⁷Li nucleus, according to the following nuclear reaction:

$^{10}_{5}B + ^{1}_{0}n_{th} \rightarrow ^{4}_{2}He + ^{7}_{3}Li + 2.79MeV$

Since the tissues also contain H and N atoms, the neutron irradiation produces secondary reactions in which proton particles and gamma radiation are produced:

$^{1}H + n_{th} \rightarrow ^{2}H + \gamma$

$^{14}N + n_{th} \rightarrow ^{14}C + p$

I hope it helps you!

4 0

4 years ago

Starting with 9.3 moles of O2, how many moles of H2S will be needed and how many moles of SO2 will be produced in the following

tensa zangetsu [6.8K]

Answer: The amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles

Explanation:

We are given:

Moles of oxygen gas = 9.3 moles

The chemical equation for the reaction of oxygen gas and hydrogen sulfide follows:

$2H_2S+3O_2\rightarrow 2SO_2+2H_2O$

For hydrogen sulfide:

By Stoichiometry of the reaction:

3 moles of oxygen gas reacts with 2 moles of hydrogen sulfide

So, 9.3 moles of oxygen gas will react with = $\frac{2}{3}\times 9.3=6.2mol$ of hydrogen sulfide

For sulfur dioxide:

By Stoichiometry of the reaction:

3 moles of oxygen gas produces 2 moles of sulfur dioxide

So, 9.3 moles of oxygen gas will produce = $\frac{2}{3}\times 9.3=6.2mol$ of sulfur dioxide

Hence, the amount of hydrogen sulfide needed is 6.2 moles and amount of sulfur dioxide gas produced is 6.2 moles

7 0

3 years ago

Chlorine atom

irina [24]

Answer:

C. Decomposition of potassium permanganate(Heating)

Explanation:

The equation of the reaction is given as;

2KMnO4 -> K2MnO4 + MnO2(s) + O2(g)

Reactant = 2KMnO4

Products = K2MnO4 + MnO2(s) + O2(g)

A. Oxygen turned in to carbon dioxide

Incorrect option - Oxygen is not the reactant

B. Sulphate and lithium boiled

Incorrect option - Sulphate and lithium are not part of this reaction

C. Decomposition of potassium permanganate(Heating)

Correct option - potassium permanganate decomposed to form K2MnO4 + MnO2(s) + O2(g)

D. None of the above

Incorrect option

8 0

3 years ago

Consider the following elementary reaction:

Marat540 [252]

Answer:

$[NO]=\frac{k_{-1}}{k_1} [N_2O_2]$

Explanation:

Hello!

In this case, since the reaction may be assumed in chemical equilibrium, we can write up the rate law as shown below:

$r=-k_1[NO]+k_{-1}[N_2O_2]$

However, since the rate of reaction at equilibrium is zero, due to the fact that the concentrations remains the same, we can write:

$0=-k_1[NO]+k_{-1}[N_2O_2]$

Which can be also written as:

$k_1[NO]=k_{-1}[N_2O_2]$

Then, we solve for the concentration of NO to obtain:

$[NO]=\frac{k_{-1}}{k_1} [N_2O_2]$

Best regards!

8 0

3 years ago

Is changing direction acceleration?

lilavasa [31]

Yes... the change of direction results in acceleration

5 0

3 years ago