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3 years ago

This drawing shows the internal anatomy of a sponge.

Chemistry

1 answer:

Evgen [1.6K]3 years ago

6 0

Answer:

there is no drawing

Explanation:

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Material use make car tyres and chewing gum?

Ulleksa [173]

Answer:

Rubber

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3 years ago

Why weren’t scientists initially concerned that the ocean absorbs excess carbon dioxide?

nasty-shy [4]

They only discovered

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3 years ago

During the naval battles of the South Pacific in World War II, the U.S. Navy produced smoke screens by spraying titanium tetrach

hammer [34]

Explanation:

The reaction given is;

TiCl4 + H2O --> TiO2 + HCl

The reaction is not balanced, upon balancing it is given as;

TiCl4 + 2H2O → TiO2 + 4HCl

a. How many moles of H2O are needed to react with 6.50 moles of TiCl4?

From the reaction;

1 mol of TiCl4 requires 2 mol of H2O

6.50 mol of TiCl4 would require x mol of H2O

1 = 2

6.5 = x

x = 6.5 * 2 / 1 = 13.0 mol

b. How many moles of HCl are formed when 8.44 moles of TiCl4 react?

From the equation of the reaction;

1 mol of TiCl4 reacts to form 4 mol of HCl

8.44 mol of TiCl4 reacts to form x mol of HCl

1 = 4

8.44 = x

x = 8.44 * 4 / 1 = 33.76 mol

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3 years ago

A first-order reaction has a half-life of 16.7 s . How long does it take for the concentration of the reactant in the reaction t

andrew11 [14]

It takes 33.4 s for the concentration of A to fall to one-fourth of its original value.

A <em>half-life</em> is the time it takes for the concentration to fall to half its original value.

Assume the initial concentration is 1.00 mol/L. Then,

$\text{1.00 mol/L }\stackrel{\text{1st half-life }}{\longrightarrow}\text{ 0.50 mol/L } \stackrel{\text{ 2nd half-life }}{\longrightarrow}\text{0.25 mol/L}\\$

The concentration drops to one-fourth of its initial value in two half-lives.

∴ Time = 2 × 16.7 s = 33.4 s

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3 years ago

Identify the intermediate leads to the major product for the reaction of 2-methyl-2-butene with hydrogen bromide in the presence

pishuonlain [190]

Answer:

Explanation:

We must have a good idea of the fact that there are two mechanisms that come into play when we are discussing about the addition of hydrogen halides to alkenes. The first is the ionic mechanism and the second is the radical mechanism.

The ionic mechanism is accounted for by the Markovnikov rule while the radical mechanism occurs in the presence of peroxides and is generally referred to as anti Markovnikov addition.

The intermediate in anti Markovnikov addition involves the most stable radical, in this case, it is a tertiary radical as shown in the images attached. The most stable radical is II hence it leads to the major product shown in the other image.

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3 years ago