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Alex787 [66]
3 years ago
14

A piecewise function is defined as shown. StartLayout enlarged left-brace 1st Row 1st column negative x , 2nd column x less-than

-or-equal-to negative 1 2nd Row 1st column 1, 2nd column x = 0 3rd Row 1st column x + 1, 2nd column x greater-than-or-equal-to 1 EndLayout What is the value of f(x) when x=3? −3 −2 1 4
Mathematics
2 answers:
mamaluj [8]3 years ago
7 0

Answer:

4

Step-by-step explanation:

allsm [11]3 years ago
5 0

Answer:

4

Step-by-step explanation:

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Please help !!!!!!!11
musickatia [10]

Step-by-step explanation:

<DBA=180 since it is a straight line

<HBA=73

mHG=73

6 0
3 years ago
F(x)=-x2+8x-1 find f(3) show work
r-ruslan [8.4K]
F(3)= -(3)^2+8(3)-1
=14
6 0
3 years ago
If UV ≅ UX and WX=23, what is VW?<br><br> VW =
KiRa [710]
<h2>Answer: </h2>

The length of VW is 23°

<h2>Step-by-step explanation: </h2><h3>Known : </h3>
  • UV = UX
  • WX = 23  

<h3>Asked : </h3>

VW = ?

<h3>Solution : </h3>

Since the UV line and UX line has the same length, so the VW line should have the same length as the WX line.

VW = WX

23 = 23

<h3>Conclusion : </h3>

The length of VW is 23°

5 0
3 years ago
What is the least common multiple<br> 8 and 12?
Anna35 [415]

Answer:

24

Step-by-step explanation:

8 x 3 = 24

12 x 2 = 24

so 24 is your least common multiple

5 0
3 years ago
Read 2 more answers
Caroline has some dimes and some quarters. She has a maximum of 15 coins worth at least $2.85 combined. If Caroline has 3 dimes,
gayaneshka [121]

Answer:

11, 12.

Step-by-step explanation:

Let q represent number of quarters.

We have been given that Caroline has a maximum of 15 coins worth at least $2.85 combined. We are also told that Caroline has 3 dimes. This means that total coins are less than or equal to 15.

We can represent this information in an inequality as:

q+3\leq 15...(1)

We are also told that the coins worth at least $2.85 combined. This means that the worth of all coins is greater than or equal to 2.85.

We know that each dime is worth $0.10 and each quarter is worth $0.25.

0.25q+3(0.10)\geq 2.85...(2)

Now, let us solve our system of inequalities.

From 1st inequality, we will get:

q+3-3\leq 15-3

q\leq 12

From 2nd inequality, we will get:

0.25q+0.30\geq 2.85

0.25q+0.30-0.30\geq 2.85-0.30

0.25q\geq 2.55

\frac{0.25q}{0.25}\geq \frac{2.55}{0.25}

q\geq 10.2

Upon combining our both inequalities, we will get:

10.2\leq q\leq 12

This means that numbers of quarters would be greater than or equal to 10.2 and less than or equal to 12.

Since we cannot have 0.2 of a coin, therefore, Caroline could have 11 or 12 quarters.

6 0
3 years ago
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