C = 5/9(F - 32)
C = -30
-30 = 5/9(F - 32)
-30 = 5/9F - 160/9
-30 + 160/9 = 5/9F
-270/9 + 160/9 = 5/9F
-110/9 = 5/9F
-110/9 * 9/5 = F
- 990/45 = F
- 22 = F
C = 5/9(F - 32)
C = 130
130 = 5/9F - 160/9
130 + 160/9 = 5/9F
1170/9 + 160/9 = 5/9F
1330/9 = 5/9F
1330/9 * 9/5 = F
11970/45 = F
266 = F
So in Fahrenheit temp, the the car is protected between -22 F and 266 F
Answer:
opp/adj
havent u pay attention in ur math class?
you will have to find the opp using a^2+b^2+c^2
Step-by-step explanation:
Answer:
???
Step-by-step explanation:
Step-by-step explanation:
∆TSU=∆RSU (SAS).
HENCE,
NONe of the above statement is true.