I need help with this math question

Mathematics

1 answer:

otez555 [7]3 years ago

3 0

Answer:

A. g(x) = 2∛x

Step-by-step explanation:

Given

Function f(x) = ∛x

The transformation of f(x) is g(x)

As we see on the graph the function g(x) is the stretched form of f(x) and there is no horizontal or vertical shift

So It is achieved as:

g(x) = kf(x), where k > 1

Correct answer choice is

A. g(x) = 2∛x

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Ayudaaa plis 7-4= 6-2= -3-2= -8+9= -9+5= 1+10=

vladimir2022 [97]

Answer:

7-4=3

6-2=4

-3-2= -5

-8+9=1

-9+5= -4

1+10=11

Step-by-step explanation:

No es tan difícil, puedes g0oglearlo

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3 years ago

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A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$