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IceJOKER [234]
3 years ago
7

The London School of Economics and the Harvard Business School have conducted studies of how chief executive officers (CEOs) spe

nd their time. These studies have found that CEOs spend many hours per week in meetings that include conference calls, business meals, and public events. Suppose that the data below show the time spent per week in meetings (hours) for a sample of 25 CEOs.
14 15 18 23 15
19 20 13 15 23
23 21 15 20 21
16 15 18 18 19
19 22 23 21 12
a. What is the least amount of time spent per week on meetings? The highest?
b. Use a class width of two hours to prepare a frequency distribution, a relative frequency distribution, for the data.
Mathematics
1 answer:
Nataly [62]3 years ago
4 0

Answer:

(a) The least amount of time spent per week on meetings is, 12 hours.

The highest amount of time spent per week on meetings is, 23 hours.

(b) Shown below.

Step-by-step explanation:

(a)

Arrange the data in ascending order.

S = {12 , 13 , 14 , 15 , 15 , 15 , 15 , 15 , 16 , 18 , 18 , 18 , 19 , 19 , 19 , 20 , 20 , 21 , 21 , 21 , 22 , 23 , 23 , 23 , 23}

The least amount of time spent per week on meetings is, 12 hours.

The highest amount of time spent per week on meetings is, 23 hours.

(b)

The frequency distribution table with the relative frequency distribution is as follows:

Class Interval   Frequency        Relative Frequency

    12 - 14                         3                            0.12

    15 - 17                         6                            0.24

    18 - 20                 8                            0.32

    21 - 23                 8                            0.32

     Total                        25                             1.00

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NeX [460]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

1.- f(x) = 5x³ - 31x² - 129x + 27

a) f(9) = 5(9)³ - 31(9)² - 129(9) + 27

   f(9) = 5(729) - 31(81) - 1161 + 27

   f(9) = 3645 - 2511 - 1161 + 27

   f(9) = 0

b.- I will use synthetic division

                        5   - 31  -129  + 27       9

                               45   126  -27                            

                        5     14     -3       0

    Trinomial = 5x² + 14x - 3

Factor               5x² + 15x - 1x - 3

                        5x(x + 3) - 1(x + 3)

b)                           (x + 3)(5x - 1)

                       x₂ + 3 = 0          5x₃ - 1 = 0

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c) The roots are x₁ = 9, x₂ = -3 and x₃ = 1/5

2.-  f(x) = 3x² + 2x - 8      factor = 3x - 4

                                     x    + 2

                       3x - 4    3x² + 2x - 8

                                   -3x² + 4x

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As the remainder was "0", 3x - 4 is a factor of 3x² + 2x - 8

3 0
3 years ago
The numerator of a rational number is greater than its denominator by 3. If the new number becomes 13/4 when the numerator is tr
GarryVolchara [31]

Answer:

Step-by-step explanation:

Let x represent the numerator and y represent the denominator.

The numerator of a rational number is greater than its denominator by 3. It means that

x = y + 3

If the new number becomes 13/4 when the numerator is tripled and the denominator is decreased by 23, it means that

3x/(y - 23) = 13/4

Cross multiplying, it becomes

3x × 4 = 13(y - 23)

12x = 13y - 299- - - - - - - - - - -1

Substituting x = y + 3 into equation 1, it becomes

12(y + 3) = 13y - 299

12y + 36 = 13y - 299

13y - 12y = 36 + 299

y = 335

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6 0
3 years ago
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alina1380 [7]
I think the answer is letter c
7 0
3 years ago
Mrs. Purdue needs to pick three random students in her class to be representatives on the student council. Explain how Mrs. Purd
Xelga [282]

Answer:

See below

Step-by-step explanation:

She could have each student in the class write his or her name on a slip of paper and put it in a bowl. Then, she could shake the bowl and pull out any slip of paper with a student's name on it. After 3 times, the random sample would be over, and Mrs. Purdue would have her 3 representatives.

5 0
2 years ago
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Natasha2012 [34]

Answer:

15/32

Step-by-step explanation:

(-3/4)÷(-8/5)

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15/32

6 0
4 years ago
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