What is the value of x? sin64°=cosx

1 answer:

5 0

We can solve for the value of x by applying the principles of sine and cosines method and laws of the inversed sign.
Given:
sin64°=cosx
Perform sin64° which is equal to 0.8987940463
0.8987940473=cosx
perform inverse sign:
cos-0.8987940473=x
x=26°
Therefore, the value of x is 26°.

You might be interested in

Magnus purchased a new car for $35,865. It depreciates about 3.6% each year. What is the value of the car after 10 years?

Naddik [55]

1 year = 3.6 % depreciation
100-3.6=96.4

so you do 35,865 ×0.964 = 34,573.86

so the price after a year is £34,573.86

to find out what the price is after 10 years you do 34,573.86 (0.964) to the power of 10
which equals £23961.73

I hope that was helpful :)

5 0

4 years ago

(-2,-9) (-1,-7) (0,-5) (1,-3) (2,-1)

Ksju [112]

What’s the question? Maybe then I can help.

4 0

3 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{12},0)(± 12 ,0)left parenthesis, plus min

lora16 [44]

Answer:

$\mathbf{\dfrac{x^2}{49^2} +\dfrac{y^2}{37^2} =1}$

Step-by-step explanation:

Given that :

the foci of the ellipse is (±√12,0) and C0-vertices are (0,±√37)

The foci are (-C,0) and (C ,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so C0-vertices are (0,±√37)

The given focus C = ae = √12

Given co-vertices ( minor axis) (0,±b) = (0,±√37)

b= √37

We can therefore express the relation between the focus and semi major axes and semi minor axes as:

$\mathbf{c^2 = a^2 - b^2 } \\ \\ \mathbf{a^2 = c^2 + b^2 } \\ \\ \mathbf{c^2 = ( \sqrt12)^2 - (\sqrt 37)^2 } \\ \\ \mathbf{c^2 = 49 } \\ \\ \mathbf{c = \sqrt{49 }}$