The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.
Given a company has 200 machines. Each machine has a 12% probability of not working.
If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.
So
1) probability that 5 would not be working
C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵
≈ 0.18665
2) probability that at least one machine would be working
0.88⁴⁰ ≈ 0.00602
3) probability that all would be working
1 - 0.12⁴⁰ ≈ 1.0000
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Answer:
The numbers are 2 , 4 , 6 or 6 , 4 , 2
Step-by-step explanation:
For solution kindly refer to the attachment .
<u>Related</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u><u> </u>
• The sum of n terms of an AP is ,
=> S = n/2 [ 2a + ( n - 1 ) d ]
• The nth term of an AP is ,
=> T_n = a + ( n - 1 ) d
1. The answer would be "-15" since integers are composed of whole numbers and negatives.
2. The statement "<span>Every real number is a rational number." is false, since real numbers are composed of both rational and irrational numbers.
3. The number "</span><span>8.52624 . . ." because this is the only non-terminating number, which makes it the only irrational number on the list.
4. "</span><span>Irrational numbers cannot be classified as rational numbers." is the only correct statement. No irrational numbers can be rational numbers, and the opposite is also true.
5. Only the statement "</span><span>Every irrational number is a real number.</span>" is true.
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14 added to the difference of 9 and 2 is the correct answer because first 2 is being subtracted from 9 and then 14 is added
