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Dmitrij [34]
3 years ago
9

Here is rectangle A. Block A. Rectangle B is ¹/₅ longer than A Block B. Rectangle C is ¹/₃ longer than B Block C. The total leng

th of all three rectangles is 133 cm. How much longer is rectangle C than B?
Mathematics
1 answer:
Hoochie [10]3 years ago
7 0

Answer:

Rectangle C is 14 cm longer than B

Step-by-step explanation:

Let  x be the length of Rectangle A. Rectangle B is ¹/₅ longer than A Block B,

Therefore the length of rectangle B is:

x+\frac{1}{5}x

Rectangle C is ¹/₃ longer than B, therefore the length of rectangle c is:

x+\frac{1}{5}x+\frac{1}{3}(x+\frac{1}{5}x) =x+ \frac{1}{5}x+\frac{1}{3}x+\frac{1}{15}x=x+\frac{9}{15}x

The total length of all three rectangles is 133 cm.

Length of rectangle A + Length of rectangle B + Length of rectangle C = 133 cm

x+x+\frac{1}{5}x +x+\frac{9}{15}x=133\\x+x+x+\frac{1}{5}x +\frac{9}{15}x=133\\3x+\frac{12}{15}x=133\\ 45x+12x=1995\\57x=1995\\x=35cm

Therefore the length of rectangle A is 35 cm, the length of rectangle B is 35+\frac{1}{5}*35=42\ cm and the length of rectangle C is 35+\frac{9}{15}*35=56\ cm

Rectangle C is ¹/₃ longer than B, which is 14 cm (42\3) longer than B

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Measure of Hypotaneous = 5√5

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By using pythagoras theorem:

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Let's substitute for b as 2a in above equation we'll get:

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Therefore,
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Answer:

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b) The inequality graph is attached.

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Step-by-step explanation:

According to the Question,

a) For the benzene to remain in liquid form, the temperature of benzene must be less than the boiling point and greater than the boiling point. Let x be the temperature of benzene, For benzene to remain as liquid, its temperature must be between:

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We will need like a graph for that
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7b + 3 – 4b = 3 – 3(b + 4)
svlad2 [7]

Hello from MrBillDoesMath!

Answer:  b

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7b + 3 - 4b = 3 - 3(b+4)  =>

7b + 3 - 4b = 3 - 3b -12 =>

(7b - 4b) + 3   = -3b - 9 =>

3b + 3 = -3b -9    =>      Add 9 to both sides

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