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Flauer [41]
4 years ago
4

Pepper Jackie used a precision hydrometer to perform an experiment to local restaurants to determine which restaurant uses the m

ost sugar in their beverages. She randomly tested 15 different types of beverages at each location to perform the conversion to calculate the amount of sugar in grams. The results of the experiment are displayed in the box plots below. Which description most accurately summarizes the sample results?

Mathematics
2 answers:
andre [41]4 years ago
8 0

Answer:

its a the answer is A

Step-by-step explanation:

zlopas [31]4 years ago
5 0

Answer:

Both have about the same range of sugar,but Jim's jint uses more sugar overall.

Step-by-step explanation:

We will compare the sugar content of both the juice bars:

Jim's juice joint

65,65,65,66,66,67,69,72,73,75,75,78,80,82,85

The Zest nest

22,25,25,28,30,32,35,35,35,40,42,42,44,45,46

We can see that The zest nest uses less sugar than the Jim's joint.

There are 2 options that seem correct.

The Zest nest is more consistent in their use of sugar in their beverages, and uses less sugar than Jim's juice joint overall.

There can also be another answer that seems true. The first one.

If we see the range, the Jim's variations is 85-65=20 and zest's variation is 46-22=24 which is very close to each other. But overall Jim's uses more sugar.

So, the answer will be the first one. Now, I'll take the first one to be true.

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We know that:

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Here x=3\theta so:

1-2\sin^2(3\theta)=\cos(2\cdot3\theta)=\cos(6\theta)
5 0
4 years ago
Please help thank you.
sveta [45]
Look at Arc DE

DE = 124°

∠A is 1/2 of Arc DE

124/2 = 62°

B.62 Degrees is your answer

hope this helps
5 0
3 years ago
The coach paid $246 for 12<br>basketball uniforms. What<br>is the unit price?​
kozerog [31]

The Unit Price is 20.5

4 0
4 years ago
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and
Ksju [112]

Answer:

A) 1

B) 1

C) 0

Step-by-step explanation:

The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. Suppose that a random sample of n = 49 customers is observed. Find the probability that the average time waiting in line for these customers is A) Less than 10 minutes B) Between 5 and 10 minutes C) Less than 6 minutes

We solve this question using the z score formula

z = (x-μ)/σ/√n, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

n = number of random samples

A) Less than 10 minutes

x < 10

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x<10) = 1

B) Between 5 and 10 minutes

For x = 5 minutes

z = 5 - 8.2/ 1.5 / √49

z = -14.93333

P-value from Z-Table:

P(x = 5) = 0

For x = 10 minutes

z = 10 - 8.2/ 1.5 / √49

z = 8.4

P-value from Z-Table:

P(x = 10) = 1

The probability that the average time waiting in line for these customers is between 5 and 10 minutes

P(x = 10) - P(x = 5)

= 1 - 0

= 1

C) Less than 6 minutes

x < 6

z = 6 - 8.2/ 1.5 / √49

z = -10.26667

P-value from Z-Table:

P(x<6) = 0

6 0
3 years ago
How do I do this ??
Nostrana [21]

Answer:

If I'm not mistaking, they want you to find the number in the middle that's between X and Z.

That number would be 3.

Hope this helps a bit! :)

4 0
3 years ago
Read 2 more answers
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