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3 years ago

To solve a literal equation xm=x+z solving for x

Mathematics

2 answers:

Marat540 [252]3 years ago

5 0

xm =x+z

subtract x from each side

xm -x = z

factor out an x

x(m-1) = z

divide both sides by m-1

x = z/(m-1)

Mariulka [41]3 years ago

3 0

Step-by-step explanation:

xm = x + z

xm - x = z

x = z/(m - 1)

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Would it be factoring a polynomial,

alukav5142 [94]

Factoring a polynomial

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3 years ago

place the following steps in order to complete the square and solve the quadratic equation, x^2-6x+7=0

MatroZZZ [7]

We have that
x²<span>-6x+7=0
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(x²-6x)+7=0
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(x²-6x+9-9)+7=0
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4 0

3 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

2 years ago

Apply the distributive property and the greatest common factor to write an equivalent expression.

amid [387]

Here, Your Original expression is 60x - 24.

Take 12 as common, which is GCD of 24 & 60,

Therefore, It would be:

60x - 24
= 12 * 5x - 12 * 2
= 12 (5x - 2)

In short, your Answer would be 12(5x - 2)

Hope this helps!

Photon

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3 years ago

Six times a number is 240 what is the number?

sweet-ann [11.9K]

240/6=40 hope this helps

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2 years ago