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poizon [28]
3 years ago
12

To solve a literal equation xm=x+z solving for x

Mathematics
2 answers:
Marat540 [252]3 years ago
5 0

xm =x+z

subtract x from each side

xm -x = z

factor out an x

x(m-1) = z

divide both sides by m-1

x = z/(m-1)

Mariulka [41]3 years ago
3 0

Step-by-step explanation:

xm = x + z

xm - x = z

x = z/(m - 1)

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alukav5142 [94]
Factoring a polynomial
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3 years ago
place the following steps in order to complete the square and solve the quadratic equation, x^2-6x+7=0
MatroZZZ [7]
We have that
x²<span>-6x+7=0
</span>Group terms that contain the same variable
(x²-6x)+7=0
Complete the square  Remember to balance the equation
(x²-6x+9-9)+7=0
Rewrite as perfect squares
(x-3)²+7-9=0
(x-3)²-2=0
(x-3)²=2
(x-3)=(+/-)√2
x=(+/-)√2+3

the solutions are
x=√2+3
x=-√2+3



4 0
3 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
2 years ago
Apply the distributive property and the greatest common factor to write an equivalent expression.
amid [387]
Here, Your Original expression is 60x - 24.

Take 12 as common, which is GCD of 24 & 60, 

Therefore, It would be: 

60x - 24
= 12 * 5x - 12 * 2
= 12 (5x - 2)

In short, your Answer would be 12(5x - 2)

Hope this helps!

Photon
5 0
3 years ago
Six times a number is 240 what is the number?
sweet-ann [11.9K]

240/6=40 hope this helps


7 0
2 years ago
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