That would be in the II quadrant
So across to negative 6 and up to 7 is your coordinate
When we reflect a point across y=x, the x and y coordinates switch out , that is (x,y) becomes (y,x) . SO for point (1,2), on reflection across y=x, (1,2) becomes (2,1) . And when we do reflection across y=-x, (x,y) becomes (-y,-x). Therefore point (2,1) on reflection across y=-x becomes(-1,-2) .
So the final answer is (-1,-2) .
Is that the whole equation? Exactly from the book or paper?
Answer:
x = 14
Step-by-step explanation:
The triangle has 2 congruent legs and is isosceles with 2 base angles being congruent , then
5x = 3x + 28 ( subtract 3x from both sides )
2x = 28 ( divide both sides by 2 )
x = 14
Answer:
Step-by-step explanation:
Slope intercept form: y = mx + b
Find slope:
m = (y₂ - y₁) / (x₂ - x₁)
= (-5 - (-4)) / (0 - 4)
= -1 / -4
= 1/4
Find y intercept using anyone of the given points and slope from above:
y = mx + b
b = -5
Now use the above slope and y intercept to create equation of a line:
