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3 years ago

Find the 8th term of the geometric sequence, given the first term and common ratio. a1=6 r=-1/3

Mathematics

1 answer:

Damm [24]3 years ago

8 0

The rule of a geometric sequence:

$a_n=a_1r^{n-1}$

We have:

$a_1=6;\ r=-\dfrac{1}{3}$

Find $a_8=?\to n=8$

substitute:

$a_8=6\cdot\left(-\dfrac{1}{3}\right)^{8-1}=6\cdot\left(-\dfrac{1}{3}\right)^7=6\cdot\left(-\dfrac{1}{2187}\right)=-\dfrac{2}{729}$

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In the long run, the probability distribution vector Xm approaches the probability distribution vector $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$ .

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